Answer:
Compound A: 1-bromo-1-methylcyclohexane
Compound B: 1-methylcyclohex-1-ene
Explanation:
In this question, we can start with the <u>I.D.H</u> (<em>hydrogen deficiency index</em>):
In the formula we have 7 carbons, 13 hydrogens, and 1 Br, so:
We have an <u>I.D.H value of one</u>. This indicates that we can have a <u>cyclic structure or a double bond</u>.
We have to keep in mind that the Br atom must be bonded to a t<u>ertiary carbon</u>. <u>We can not have a double bond</u> because in the ozonolysis reaction we have only <u>1 product</u>, therefore, we can not have a double bond in the initial molecule (if we have a double bond in the initial molecule we will have more than 1 product in the ozonolysis reaction).
With this in mind, we will have a <u>cyclic structure</u>. If we have 7 carbons and we need a tertiary alkyl halide. We can have a cyclic structure of 6 members and a methyl group bonded to a carbon that also is bonded to a Br atom <u>(1-bromo-1-methylcyclohexane).</u>
In the reaction with we will have an <u>elimination reaction</u>. In other words, we have the production of a double bond inside of the cyclic structure <u>(1-methylcyclohex-1-ene)</u>.
See figure 1 for further explanations.
I hope it helps!