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RUDIKE [14]
3 years ago
15

Which of these is not characteristic of carbon?

Chemistry
2 answers:
torisob [31]3 years ago
4 0

The correct answer is d.

C has four valence electrons. To become an ion with a complete valence shell, it would have to

  • • Gain four electrons to become C⁴⁻  or
  • • Lose four electrons to become C⁴⁺

Thus, carbon is extremely unlikely to form ionic compounds.

MrMuchimi3 years ago
4 0

Answer:

Option d

Explanation:

Carbon is a non-metal. Atomic number of carbon is 6.

Electronic configuration of C = 1s^22s^22p^2

Its outer shell has 4 valence electrons. Carbon forms covalent bond by sharing its valence electrons. So, carbon completes its octate by sharing its four valence electrons.

Catenation is the characterisctics property of carbon. Catenation is the property of elements in which atoms of same element bond with itself in a series to form long chain.

Elements usually form bond in order to attain stability.

Carbon does not form ionic bond, as removal of 4 electrons or gain of 4 electrons is not possible in order to attain inert gas configuration.

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Read 2 more answers
For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

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       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

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