J. J. Thompson's experiment with the cathode ray tube lead to the invention of television. The correct option among all the options given in the question is option "c".J. J. Thompson was born on 18th of December in the year 1856 and died on 30th of August in the year 1940. He was an English physicist who was born in Manchester of United Kingdom. He was awarded with the Nobel Prize in Physics for his discovery of electron in the year 1897. The best part was that his son also got awarded with the Nobel Prize later on along with eight of his students.
Answer:
Choice B, C, and D.
Explanation:
Choice A is not true in general. Here's a way to think about that. Consider a very special equilibrium where the concentration of reactants and products are indeed equal. When one of the external factors (such as temperature) changes, the equilibrium will shift towards either side of the reaction. More products will be converted to reactants, or vice versa. Either way, in the new equilibrium, the concentration of the reactants and products will not be equal any more.
Choice B should be considered with choice C and D in mind.
Choice C is indeed correct. The reaction rate would not be zero unless all the reactants were used up or taken out of the system. That's not what happens in an equilibrium. Instead, when reaction rate is plotted against time, the graph for reactions in both directions will eventually flat out at a non-zero value.
Choice D explains why even though choice C is correct, the concentration of a system at equilibrium stays the same. At the equilibrium, reactions in both directions are still happening. However, during the time it takes for the forward reaction use up some reactant particles, the reverse reaction would have produced these particles again. On a large scale, there would be no observable change to the concentration of each species in the equilibrium. Therefore, choice B is also correct.
In this situation we need to balance the two half cell equations to form a proper reaction. This means reversing one of the two half-cell equations and balancing.
In this case we do not need to actually worry about balancing because the electrical potentials for each half reaction remain unchanged regardless of reactant and product quantities. What does change however, is the sign of the electrical potential. As we are reversing one half-cell reaction, it's electrical potential will be reversed aswell. Then the overall cell potential is the sum of these two potentials.
The anode reaction is Fe3+ + e -> Fe2+ as it requires electrons as reactants and as a positive electrical potential, meaning this reaction favours the products. The cathode reaction is therefore manganese.
So the overall electrical potential Ecell = Ecathode - Eanode
Ecell = -1.18V - 0.77 = -1.95V
(remember we switch the polarity of the electrical potential for the reaction that we reverse, in this case the anode reaction involving iron).
Answer:
141.604°C
Explanation:
PV=nRT
8.3 x 14= 10 x 0.08206 x T
116.2= 0.8206T
116.2\0.8206 = T
141.604
