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meriva
3 years ago
14

9. A contractor is considering a sale that promises a profit of $27,000 with a probability of 0.7 or a loss (due to bad weather,

strikes, and such) of $12,000 with a probability of 0.3. What is the expected value?
Mathematics
1 answer:
allochka39001 [22]3 years ago
4 0

Answer:

Hence the expected value for the contractor for sales is 15,300 $.

Step-by-step explanation:

Given:

Winning $27000 is 0.7 and losing 12000 $ of it about 0.3

To find :

Expected value for the contractor for sales.

Solution:

Th expected value is the average occurred  of the event.

<em>{Suppose </em>

<em>a series of number like 10,30,30,30,30,60,78.</em>

<em>for this  expected value will be</em>

<em>(10+30+30+30+30+60+78+78) / 8</em>

<em>=10(1/8)+30(4/8)+60(1/8)+78(2/8).</em>

<em>78 ,10 ,30 and 60 are just like cost and 1/8 ,4/8,2/8 are probabilities of respective cost</em>.

}

Similar for given values

Expected value with probability is =

Winning probability *cost of winning +(-losing probability * losing cost)

losing means negative impact on value so it is negative

=27000*0.7-12000*0.3

=18900-3600.

=15300 $.

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Subtraction of normal variables:

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The width of a casing for a door is normally distributed with a mean of 24 in and a standard deviation of 0.14 in.

This means that \mu_{C} = 24, \sigma_{C} = 0.14

The width of a door is normally distributed with a mean of 23.87 in and a standard deviation of 0.08 in.

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The mean is:

\mu = \mu_{C} - \mu_{D} = 24 - 23.87 = 0.13

The standard deviation is:

\sigma = \sqrt{\sigma_{C}^2+\sigma_{D}^2} = \sqrt{0.14^2+0.08^2} = 0.1612

Probability:

This probability is 1 subtracted by the pvalue of Z when X = 0.25. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.25 - 0.13}{0.1612}

Z = 0.74

Z = 0.74 has a pvalue of 0.7704

1 - 0.7704 = 0.2296

0.2296 = 22.96% probability that the width of the casing exceeds the width of the door by more than 0.25 in.

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