Question

Container A has 200 L of water, and is being filled at a rate of 6 liters per minute. Container B has 500 L of water, and is being drained at 6 liters per minute. How many minutes, m, will it take for the two containers to have the same amount of water?​

Answer 1

Answer:

25 minutes

Step-by-step explanation:

Let the amount of time, in minutes, be x.

For Container A, we can write:

200 + 6x [since it has 200 and is being filled with 6 per minute]

For Container B, we can write:

500 - 6x [since it has 500 and is being drained with 6 per minute]

To find, we equate them and solve for x:

$200+6x=500-6x\\6x+6x=500-200\\12x=300\\x=\frac{300}{12}\\x=25$

So, in 25 minutes (m), the two containers will have same amount of water