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DanielleElmas [232]
3 years ago
8

What is the solution to the system of equations {−3x+5y=12 7x−5y=−28?

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0

Answer:

\boxed{x = -4~~and~~y = 0}

.

Step-by-step explanation:

Use elimination

-3x + 5y = 12

<u>7x - 5y = -28  </u>+

4x = -16

x = \frac{-16}{4}

x = -4

.

Subsitute the value of x to one of equations

-3x + 5y = 12

-3(-4) + 5y = 12

12 + 5y = 12

5y = 12 - 12

5y = 0

y = \frac{0}{5}

y = 0

.

Happy to help :)

V125BC [204]3 years ago
5 0

Answer:

x=-4 and y=0

Step-by-step explanation:

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P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

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