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OLEGan [10]
3 years ago
9

A gallon of mik us about the same as 4 l of milk. about how many liter of milk are there in 10 gal

Mathematics
1 answer:
Anna [14]3 years ago
5 0
The answer is 37.8541178
 hope this helps ;)

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A cylinder has a radius of 6 inches and a height of 15 inches. What is the surface area of the cylinder? Express the answer in t
shutvik [7]

Answer:

The surface area for this cylinder is 252*pi square inches.

Step-by-step explanation:

The surface area of a cylinder can be calculated by using the following formula:

surface area = 2*pi*r² + 2*pi*r*h

Applying the data from the problem, we have:

surface area = 2*pi*(6)² + 2*pi*(6)*15

surface area = 2*pi*36 + 180*pi

surface area = 72*pi + 180*pi

surface area = 252*pi

The surface area for this cylinder is 252*pi square inches.

4 0
3 years ago
Read 2 more answers
A point p in the first quadrant lies on the parabola y=x^2. Express the coordinates of p as a function of the angle of inclinati
max2010maxim [7]

Answer:

  • The coordinates of the point p are:       (x,xtan\alpha )

                   

           

Explanation:

1. Name the angle of inclination of the line joining p to the origin α.

2. Find the relation between the coordinates of the point (x,y)

When you draw a line from the origin to the parabola, the intersection point, p(x,y) will have coordinates (x,y).

As per the definition of the tangent trigonometric ratio you have:

  • tan\alpha =\frac{y}{x}

From which you can clear y:

  • y=xtan\alpha =>(x,y)=(x,xtan\alpha )

Which is the expression of the coordinates of p as a function of the angle of inclination of the line joining p to the origin.

8 0
3 years ago
Petes boat can travel 48 miles upstream in 4 hours. The return trip takes 3 hours. Find the speed of the boat in still water and
tankabanditka [31]
So... hmm bear in mind, when the boat goes upstream, it goes against the stream, so, if the boat has speed rate of say "b", and the stream has a rate of "r", then the speed going up is b - r, the boat's rate minus the streams, because the stream is subtracting speed as it goes up

going downstream is a bit different, the stream speed is "added" to boat's
so the boat is really going faster, is going b + r

notice, the distance is the same, upstream as well as downstream
thus   \bf \begin{cases}
b=\textit{rate of the boat}\\
r=\textit{rate of the river}
\end{cases}\qquad thus
\\\\\\

\begin{array}{lccclll}
&distance&rate&time(hrs)\\
&----&----&----\\
upstream&48&b-r&4\\
downstream&48&b+4&3
\end{array}
\\\\\\

\begin{cases}
48=(b-r)(4)\to 48=4b-4r\\\\
\frac{48-4b}{-4}=r\\
--------------\\
48=(b+r)(3)\\
-----------------------------\\\\
thus\\\\
48=\left[ b+\left(\boxed{\frac{48-4b}{-4}}\right) \right] (3)
\end{cases}

solve for "r", to see what the stream's rate is

what about the boat's? well, just plug the value for "r" on either equation and solve for "b"
5 0
3 years ago
PLEASE HELP! ITS DUE SOON!!!! I DONT GET THIS!!
o-na [289]

Answer:

d. 50°

Step-by-step explanation:

Since you know one angle and its opposite side, use the law of sines.

sin 36°/11.9 = sin D/15.6

sin D = 15.6 × sin 36° / 11.9

sin D = =0.7705

D = sin^-1 0.7705

D = 50.4°

8 0
2 years ago
How would it be written out though?
ankoles [38]

Answer:

Wait what do you mean by this?

3 0
3 years ago
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