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3 years ago

Find the perimeter Simplify your answer completely

Mathematics

2 answers:

Allushta [10]3 years ago

7 0

Perimeter = 9/2 + 17/2 + 52/5 + 52/5 + 64/5 + 67/4

= 26/2 + 168/5 + 67/4

= 13 + 33.6 + 16.75

= 63.35 units.

Lubov Fominskaja [6]3 years ago

4 0

Answer:

4/2+ 8/2+20/5+20/5+48/5+42/4

12/2+88/5+42/4

(120+ 352+210)/20= 682/20= 341 x 1/10=34.1

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Oakland Middle school has 128 6th graders, 121 7th graders and 135 8th graders. If there are 3 teachers per 32 students, how man

zepelin [54]

Answer:

36 Teachers in Total

Step-by-step explanation:

I would use Ratio.

Students: 128 + 121 + 135 = 384 total students

Teachers: Students

3 : 32

36 : 384

384 ÷ 32 = 12

12 x 3 = 36

6 0

3 years ago

2(x+9)= [ ]x + [ ] what is the answer I’m struggling in math rb please help!!

Anarel [89]

Answer:

2x+18

Step-by-step explanation:

We can start by distributing the 2 to each term in the parentheses...

2(x)+2(9)

Multiply

2x+18

7 0

2 years ago

Read 2 more answers

9 – 2x = 19 What is x

iren2701 [21]

9-2x=19

or,-2x=19-9

or,-2x=10

or,x=10/-2

therefore,

x=-5

6 0

4 years ago

Read 2 more answers

Here is a triangular pyramid and its net.

bazaltina [42]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$

${\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}$

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

$\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}$

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

$\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}$

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to Lateral Surface Area + Area of base

$\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\ mm^{2}$

Hence,

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

3 0

3 years ago

When f(x)=5x^2-2x+5, evaluate f(-3)

patriot [66]

Answer:

f(-3)=56

Step-by-step explanation:

When evaluating a specific input for a function, you just plug that input in for x.

So in this case, f(-3)=5(-3)^2-2(-3)+5

f(-3)=5(-3)^2-2(-3)+5

f(-3)=5(9)+6+5

f(-3)=45+6+5

f(-3)=56

8 0

3 years ago