Answer:
Explanation:
Given
Initial Intensity of light is S
when an un-polarized light is Passed through a Polarizer then its intensity reduced to half.
When it is passed through a second Polarizer with its transmission axis 
here 
When it is passed through third Polarizer with its axis 
to first but 
to second thus 
When middle sheet is absent then Final Intensity will be zero
The work done by the heat engine is 40 kCal.
The given parameters;
- input heat of the engine, Q₁ = 70 kCal
- output heat of the engine, Q₂ = 30 kCal
To find:
- the work done by the heat engine
The work done by the heat engine is the change in the heat energy of the engine;
W = Q₂ - Q₁
Substitute the given parameters and solve work done (W)
W = 70 kCal - 30 kal
W = 40 kCal
Thus, the work done by the heat engine is 40 kCal.
Learn more here: brainly.com/question/4280097
2. Groups
3.Ion
4.NonPolar
5.Metallic Bond
6.Make up most of the atom's mass
7.Atomic Number
8.Seven
