Answer:
Torque = 0.25Nm
Explanation:
To calculate the magnitude of torque, first we must calculate the lever arm. The lever arm is perpendicular distance from the axis of rotation to the line of the action of the force.
Lever arm = r sin theta
Where r = 4.9cm= 0.049m
Theta = 30°
Lever arm = 0.049 sin30° = 0.245m
Magnitude of torque = rfsintheta
f = 1.0T
Magnitude of torque= 0.245×1.0 = 0.245Nm
To 2 significant figure=0.25Nm
1. The problem statement, all variables and given/known data A person jumps from the roof of a house 3.4 meters high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.70 meters. If the mass of his torso (excluding legs) is 41 kg. A. Find his velocity just before his feet strike the ground. B. Find the average force exerted on his torso by his legs during deceleration. 2. Relevant equations I can't even seem to figure that part out. Help please? 3. The attempt at a solution I don't know how to start this at all
a) gia tốc = vf-vi / t
a = 14-10 / 20
a = 0,2ms⁻²
b) dưới dạng a = Δv / t
v = lúc
v = 0,2 × 40
v = 8ms⁻¹
như v = d / t
do đó d = vt
d = 8 × 40
d = 320m
hãy đánh dấu là trí óc nhất
The dogs centripetal acceleration is 2.4 meters/second^2
The answer would be D. Because the iron fillings are attracted to the magnet underneath the glass.
