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Vilka [71]
3 years ago
15

You are walking on a beach and find a mystery piece of metal. You take it back to your lab and measure its mass to be 0.5 kg. In

order to heat the metal 1 degree K, you must add 115 J of heat. Identify the metal. q =mCΔT
A) Brass
B) Copper
C) Platinum
D) Silver
Physics
1 answer:
murzikaleks [220]3 years ago
7 0

D) Silver

Explanation:

Given parameters:

Mass of metal = 0.5kg

temperature change = 1K

Quantity of heat = 115J

Unknown;

Identity of the metal = ?

Solution:

We first find the specific heat of the unknown metal and compare with the table of specific heat of metals.

   C = \frac{Q}{mΔt}

  C = \frac{115}{1 x 0.5} = 230JKg⁻¹K⁻¹

Comparing this value with the table shows that the metal is silver.

Learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

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what is the main difference between a substance going through a physical change and one going through a chemical ?
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Answer: Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.

Explanation:

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What is the definition of input force?
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Answer:

The input force (effort) is the amount of effort used to push down on a rod, or pull on a rope in order to move the weight. In this example, the force the little guy is using to pull the elephant is the input force.

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In a series RLC resonance circuit, the resonance frequency f0 = 700 kHz. The resistor R = 10 Ohm. The specified bandwidth (BW) s
sladkih [1.3K]

Answer:

  • quality factor (Q) = 69.99
  • inductor = 1.591 x 10⁻⁴ H
  • capacitor = 3.248 x 10⁻¹⁰ F

Explanation:

Given;

resonance frequency (F₀) = 700 kHz

resistor, R =  10 Ohm

bandwidth (BW) = 10 kHz

bandwidth (BW)  = \frac{R}{2\pi L}

BW = \frac{R}{2\pi L}

make L (inductor) the subject of the formula

L = \frac{R}{2\pi *BW}  =  \frac{10}{2\pi *10,000} =1.591 *10^{-4} \ H = \ 0.1591\ mH

F_o =\frac{1}{2\pi\sqrt{LC} } \\\\\sqrt{LC} = \frac{1}{2\pi F_o} \\\\LC = \frac{1}{4\pi ^2F_o^2}= \frac{1}{4\pi ^2(700,000)^2} = 5.168*10^{-14}

make C (capacitor)  the subject of the formula

C = \frac{5.168*10^{-14}}{1.591*10^{-4}} = 3.248*10^{-10} \ F = \ 3.248*10^{-4} \ \mu F

quality factor (Q) = \frac{1}{R} \sqrt{\frac{L}{C}} \ = \frac{1}{10} \sqrt{\frac{1.591*10^{-4}}{3.248*10^{-10}}}=69.99

quality factor (Q) =  69.99

5 0
3 years ago
How many types of crust are there? List the names and one detail about each type
valina [46]

Answer:

There are two different types of crust: thin oceanic crust that underlies the ocean basins, and thicker continental crust that underlies the continents. These two different types of crust are made up of different types of rock.

Explanation:

There ya go !

:) hoping this helped ya out

5 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Greeley [361]

Answer:C

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