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Vilka [71]
3 years ago
15

You are walking on a beach and find a mystery piece of metal. You take it back to your lab and measure its mass to be 0.5 kg. In

order to heat the metal 1 degree K, you must add 115 J of heat. Identify the metal. q =mCΔT
A) Brass
B) Copper
C) Platinum
D) Silver
Physics
1 answer:
murzikaleks [220]3 years ago
7 0

D) Silver

Explanation:

Given parameters:

Mass of metal = 0.5kg

temperature change = 1K

Quantity of heat = 115J

Unknown;

Identity of the metal = ?

Solution:

We first find the specific heat of the unknown metal and compare with the table of specific heat of metals.

   C = \frac{Q}{mΔt}

  C = \frac{115}{1 x 0.5} = 230JKg⁻¹K⁻¹

Comparing this value with the table shows that the metal is silver.

Learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

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Answer:

Explanation:

The question is incomplete. Here is the complete question.

"Find the equivalent resistance, the current supplied by the battery and the current through each resistor when the specified resistors are connected across a 20-V battery. Part (a) uses two resistors with resistance values that can be set with the animation sliders, and you can use the animation to verify your calculation. In part (b), three resistors are specified. (a) Two resistors are connected in series across a 20-V battery. Let R1 = 1 Ω and R2 = 2 Ω. Rea = (b) Add a third resistor to the circuit in series. Let R1 = 1 Ω, R2 = 2 Ω, and R3 = 3 Ω"

Using ohms law formula to solve the problem

E = IRt

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R1 = 1ohms and R2 = 2ohms

If the resistors are Connected in series across a 20V supply voltage,

-Equivalent resistance = R1+R2

= 1ohms + 2ohms

= 3ohms

- In a series connected circuit, same current flows through the resistors.

Using the formula E = IRt

I = E/Rt

I = 20/3

I = 6.67A

The current in both resistors is 6.67A

- Different voltage flows across a series connected circuit.

Using the formula V = IR

V is the voltage across each resistor

I is the current in each resistor

For 1ohms resistor,

V = 6.67×1

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V = 6.67×2

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- Total equivalent resistance = 1+2+3

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I = 20/6

I = 3.33A

Since the same current flows through the resistors, the current across each of them is 3.33A

- Voltage across them is calculated as shown:

V = IR

For 1ohm resistor

V = 3.33×1

V = 3.33volts

For 2ohms resistor

V = 3.33×2

V = 6.66volts

For 3ohms resistor

V = 3.33×3

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