Answer:
f−1 (x) = x2 −4
Step-by-step explanation:
Answer:
it is incomplete question isnt it??
I started out with a proportion like you had, 24/16=20/x and I got 13.333. So I found the area of the big rhombus and set it equal to the smaller one. 24*20=16*x --> 480=16x and then x=30
Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Answer:
The units digit is 1.
Step-by-step explanation:
To identify the last digit or the unuts digit of a number, we use the concept of cyclicity. Numbers last digit has their own specific cycle.
The cycle for number 17,
17 - 7 (units digit)
17x17 - 9 (units digit)
17x17x17 - 3 (units digit)
17x17x17x17 - 1 (units digit)
For number 11, all units digit is 1.
For number 7, it follows the same cycle of number 17.
So 17 and 7 has 4 elements in the cycle (7, 9, 3 1) and only (1) for 11.
Divide 2012 by 4, we get 503. This means that we have 503 times the cycle of 4 is repeated. The fourth element in the cycle is 1. Thus 17^2012 has 1 as units digit,
11^2012 has 1 as units digit
And 7^2012 has 1 as units digit.
So 1+1-1 =1.
