Steps:
1. calculate the values of y at x=0,1,2. using y=5-x^2
2. calculate the areas of trapezoids (Bottom+Top)/2*height
3. add the areas.
1.
x=0, y=5-0^2=5
x=1, y=5-1^2=4
x=2, y=5-2^2=1
2.
Area of trapezoid 1 = (5+4)/2*1=4.5
Area of trapezoid 2 = (4+1)/2*1=2.5
Total area of both trapezoids = (4.5+2.5) = 7
Exact area by integration:
integral of (5-x^2)dx from 0 to 2
=[5x-x^3/3] from 0 to 2
=[5(2-0)-(2^3-0^3)/3]
=10-8/3
=22/3
=7 1/3, slight greater than the estimation by trapezoids.
Answer: x=-1
Step by step:
2|x+6|+9=19
Subtract 9 from both sides.
2|x+6|=10
Divide both sides by 2
|x+6|=5
Use the definition of absolute value.
x+6=5
Subtract 6 on both sides
x=-1
Hope this helped! :)
In both cases,
(as a consequence of the interesecting secant-tangent theorem)
So we have
10.
(omit the negative solution because that would make at least one of AB or AD have negative length)
11.
(again, omit the solutions that would give a negative length for either AB or AD)
Answer:
53/5
Step-by-step explanation:
since 10 is the denominator of the denominator we can move it to the numerator, giving us 10n/5-3n = 1/5
multiply all sides by 5-3n, giving us 10n = (5-3n)/5
now multiply by 5 to get rid of the final denomintor, 50n = 5-3n
move 3n to the other side 53n = 5, n = 53/5
Answer:
about =502.65
Step-by-step explanation:
