Hello!
First of all, let's find the triangle. As we can see, it is eight units long and four units tall. We can use the triangle formula and half the product.
4(8)=32
32/2=16
Now we need to find the area of the semicircle. We can use circle formulas and half our final answer. We will find the area using A=
r².
We know that the diameter of this circle is eight. Therefore our radius is 4.
A=
²
A=
Now we multiply.
16≈50.27
Now we add our triangle.
50.27+16=66.27
The nearest answer to this is B)66.2. It may have been a bit over as we used , not 3.14.
I hope this helps!
Answer:
35%
Step-by-step explanation:
You labeled the triangle wrong sides 'a' and 'b' are supposed to be the sides that make the right angle. the other side is called the hypotenuse which is the longest side which you should have labeled 'c'
so Pythagorean theorem says
a^2+b^2=c^2
so
(2x+1)^2+(11x+5)^2=(12x+1)^2
distribute
(4x^2+4x+1)+(121x^2+110x+25)=(144x^2+24x+1)
add like terms
125x^2+114x+26=144x^2+24x+1
subtract 125x^2 from both sides
114x+26=19x^2+24x+1
subtract 114x from both sides
26=19x^2-90x+1
subtract 26 from both sides
0=19x^2-90-25
factor
(x-5)(19x+5)=0
therefor x-5=0 and/or 19x+5=0
so
x-5=0 add 5 to both sides
x=5
19x+5=0
subtract 5 from both sides
19x=-5
divide both sides by 19
x=-5/19
since side legnths can't be negative, we can cross this solution out
so x=5
subtitute
1+2x
1+2(5)
1+10=11
side a=11
11x+5
11(5)+5
55+5=60
side b=60
12x+1
12(5)+1
60+1=60
side c=61
add them all up
side a+b+c=11+60+61=132=total legnth
