There is no solution.
Step-by-step explanation:
Given:
y = 2x + 1
4x - 2y = 4
Substitute y = 2x + 1 into 4x - 2y = 4
4x - 2(2x + 1) = 4
4x - 4x - 2 = 4
0x = 4 + 2
0x = 6
Anything to the multiple of zero is zero. Hence 0x = 0, and 0 ≠ 6
So there is no solution to the equation.
Answer:
The value of x would be 5
Step-by-step explanation:
(for future reference if you have questions like this it’s better to fill in numbers for x to be able to answer the question)
So you want to fill in x with a number. In this case in order for this equation to be right you fill x with 5.
So 5(5)+10=35
And to check your answer to make sure it’s right you would add the measure of angle R which is 55 to the measure of angle M which is 35.
55+35 is 90. Which makes your answer for x correct :) hopefully this makes sense.
In order to solve using elimination, we need to be able to get rid of one variable, so that we can solve for the other. We need to subtract these two equations given from one another, or multiply the bottom equation by a negative and add them together.
(-5x + 6y = 8) - (-5x + 4y = 2)
(-5x + 6y = 8) + (5x - 4y = -2)
0x + 2y = 6
2y = 6
y = 3
Now that we know the value of one variable, we can take that value and plug it back into one of the original equations and solve for the value of the other variable.
-5x + 6y = 8
-5x + 6(3) = 8
-5x + 18 = 8
-5x = -10
x = 2
The solution to this system of equations is (2, 3).
Hope this helps!! :)
Answer:
12 degrees
Step-by-step explanation:
8 below zero is -8.
20+ -8 = 12
Answer:
a)
![A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}](https://tex.z-dn.net/?f=A%5C%3A%3D%5C%3AP%5Cleft%281%5C%3A%2B%5C%3A%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D)
b)
The total amount accrued, principal plus interest, from compound interest on an original principal of $ 4,200.00 at a rate of 3.6% per year compounded 12 times per year over 10 years is $5667.28.
Step-by-step explanation:
a. Write the function that represents the value of the account at any time, t.
The function that represents the value of the account at any time, t
![A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}](https://tex.z-dn.net/?f=A%5C%3A%3D%5C%3AP%5Cleft%281%5C%3A%2B%5C%3A%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D)
where
P represents the principal amount
r represents Annual Rate
n represents the number of compounding periods per unit t, at the end of each period
t represents the time Involve
b) What will the value be after 10 years?
Given
The principal amount P = $4200
Annual Rate r = 3.6% = 3.6/100 = 0.036
Compounded monthly = n = 12
Time Period = t
To Determine:
The total amount A = ?
Using the formula
![A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}](https://tex.z-dn.net/?f=A%5C%3A%3D%5C%3AP%5Cleft%281%5C%3A%2B%5C%3A%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D)
substituting the values
![A\:=\:4200\left(1\:+\:\frac{0.003}{12}\right)^{\left(12\right)\left(10\right)}](https://tex.z-dn.net/?f=A%5C%3A%3D%5C%3A4200%5Cleft%281%5C%3A%2B%5C%3A%5Cfrac%7B0.003%7D%7B12%7D%5Cright%29%5E%7B%5Cleft%2812%5Cright%29%5Cleft%2810%5Cright%29%7D)
![\:A\:=\:4200\left(1.0025\right)^{120}](https://tex.z-dn.net/?f=%5C%3AA%5C%3A%3D%5C%3A4200%5Cleft%281.0025%5Cright%29%5E%7B120%7D)
$
Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 4,200.00 at a rate of 3.6% per year compounded 12 times per year over 10 years is $5667.28.