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docker41 [41]
3 years ago
10

Help me on number problem 4 please

Mathematics
1 answer:
kakasveta [241]3 years ago
7 0

Answer:

y = -1/4x + 3

Step-by-step explanation:

Because you are finding the perpendicular slope, you need to find the negative reciprocal of the original line, which would be -1/4. You then use point slope form to find the y-intercept with the slope and given point:

y - 5 = -1/4(x + 8). That equals to y = -1/4x + 3.

So the equation of this line is y = -1/4x + 3.

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Justin rode his bicycle 5.3 miles a day for 17 days straight. How many miles did Justin ride altogether during the 17-day stretc
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4 years ago
Read 2 more answers
Need Help on this assignment ASAP!
allsm [11]
The answer is y=(1/2)x -5

You are given the slope and a core donate pair so you plug them in to the equation. 2=x. -4=y. And (1/2)= m

Then work out like a one step equation

7 0
3 years ago
8x+x^2-2y-64+y^2=0 standard form with explanation
xz_007 [3.2K]
X² + 8x +y² - 2y -64 =0
We see that the equation has x² and y² . Also we see that coefficients in front of x² and y² are equal. So this is an equation of the circle.
(x² + 8x) +(y² - 2y) -64 =0
(x² + 8x) +(y² - 2y) = 64
We need to complete square for x and y groups, that means it should be written in form (a+b)² or (a-b)².
Expressions in parenthesis we will write as a²+/-2ab+b², to write it after as (a+/-b)², because  a²+/-2ab+b² = (a+/-b)²

(x² + 2*4x) +(y² - 2*1y) = 64
(x² + 2*4x+4²) +(y² - 2*1y+1²) = 64+4²+1²
(x+4)² + (y-1)²= 81 Sometimes this is called a standard form of the circle.
(x+4)² + (y-1)²= 9² Sometimes it is required to write like this.

And if you are studying circles,ellipses  and hyperbolas, the standard form should look like
\frac{(x+4)^{2}}{9^{2}} + \frac{(y-1)^{2}}{9^{2}} =1






8 0
3 years ago
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