Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x
<h3>Variation</h3>
y = k × x
4 = k × 2
4 = 2k
k = 4/2
k = 2
when y = 2 and x = 4
y = k × x
= 2 × 4
y = 8
y = k/x
4 = k / 2
8 = k
when y = 2 and x = 4
y = k/x
2 = k/4
2 × 4 = k
k = 8
So,
y = k/x
y = 8/x
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K= 10(-7) -19
k= -70-19
k=-89
Let be Z the money ;
We have ( 40 / 100 ) x Z = $85 ;
( 4 / 10 ) x Z = $85 ;
( 2 / 5 ) x Z = $85 ;
Z = $( 85 x 5 ) ÷ 3 ;
Z = $425 ÷ 3 ;
Z = $141,66 ≈ $142 ;
I'll sub my guy. Don't give up, keep climbing.
The two in the middle. B and C, I guess.
