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gulaghasi [49]
3 years ago
6

The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. Conveyor belts can vary from the ideal width by a

t most 7/32 in.
Mathematics
2 answers:
kati45 [8]3 years ago
7 0

Answer;

The acceptable width is 49 25/32 and 50 7/32

That is; 49 25/32 ≤ x ≥ 50 7/32

Explanation;

-If the ideal is 50 and the max variation is 7/32 inches, then that's 7/32 under 50 and 7/32 over 50.

Therefore; 50-7/32= 49 25/32, and 50+7/32 = 50 7/32.

x ≤ 50 7/32 and x ≥ 49 25/32

Thus; the acceptable width is 49 25/32 ≤ x ≥ 50 7/32.

sdas [7]3 years ago
5 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

If the ideal is 50 and the max variation is 7/32in, then that's 7/32 under 50 and 7/32 over 50. 
<span>So, 50-7/32= 49 25/32, and 50+7/32 = 50 7/32. </span>
<span>So the acceptable width is 49 25/32 to 50 7/32.</span>

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