200/1 times 7/8 = 1400/8 = 700/4 = 350/2 = 175
175 + 200 = 375ml
The number is 5 and the factor is 1
Roberto overtakes Juanita at the rate of (7.7 mi)/(11 h) = 0.7 mi/h. This is the difference in their speeds. The sum of their speeds is (7.7 mi)/1 h) = 7.7 mi/h.
Roberto walks at the rate (7.7 + 0.7)/2 = 4.2 mi/h.
Juanita walks at the rate 4.2 - 0.7 = 3.5 mi/h.
_____
In a "sum and diference" problem, one solution is half the total of the sum and difference. If we let R and J be the respective speeds of Roberto and Juanita, we have
R + J = total speed
R - J = difference speed
Adding these two equations, we have
2R = (total speed + difference speed)
R = (total speed + difference speed)2 . . . . . as computed above
Answer:
Step-by-step explanation:
start by subtracting the original value from the reduced value.
205.67-145.90=59.77
now compare the change of rate
59.77=r(205.67)
59.77/205.67=r
r=29%
