Answer:
E.
Explanation:
The atomic radii increase in size down the group as the number of quantum shells and subshells increase with increasing atomic number.
Answer:
40%
Explanation:
We'll begin by obtaining the molar mass of MgO. This is illustrated below:
Molar Mass of MgO = 24 + 16 = 40g/mol
Observing the formula MgO, we have 1 atom of O in it.
The percentage composition by mass of oxygen in MgO is given by:
Mass of O/Molar Mass of MgO x 100
= 16/40 x 100 = 40%
A ratio scale and a diagrammatic scale ( bar scale).
We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of
we have to dilute??
It's simple.
Using a periodic table we can find the molar mass of
Then
now we can replace it
Then we have to dilute 63.84 grams of copper (II) sulfate in 1 L of water to obtain a solution with 0.400M
Answer: The equilibrium concentration of CO at 1000 K is 0.016 M , the equilibrium concentration of at 1000 K is= 0.033 M and the equilibrium concentration of at 1000 K is 0.139 M
Explanation:
Initial concentration of
Initial concentration of
The given balanced equilibrium reaction is,
Initial conc. 0.1550 M 0.172 M 0 M
At eqm. conc. (0.1550-x) M (0.172-x) M (x) M
The expression for equilibrium constant for this reaction will be,
we are given :
Now put all the given values in this expression, we get :
Thus the equilibrium concentration of CO at 1000 K is= (0.1550-x) M =(0.1550-0.139) M = 0.016 M
Thus the equilibrium concentration of at 1000 K is= (0.172-x) M =(0.172-0.139) M = 0.033 M
Thus the equilibrium concentration of at 1000 K is= x M = 0.139 M