Question

A gas has a volume of 560 mL at a temperature of –55°C. What volume will the gas occupy at

Answer 1

Answer: 778 ml

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=560ml\\T_1=-55^oC=(273-55)K=218K\\V_2=?\\T_2=30.0^oC=(273+30.0)K=303K$

Putting values in above equation, we get:

$\frac{560ml}{218K}=\frac{V_2}{303K}\\\\V_2=778ml$

Thus volume the gas occupy at 30.0°C is 778 ml