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Mamont248 [21]
3 years ago
6

16 soccer cards and 22 baseball cards into group. What is the greatest number of cards she can put in each group? How many group

s of each type will there be?
Mathematics
1 answer:
Bond [772]3 years ago
5 0

Answer:

The greatest number of cards she can put in each group is 2.

There will be 8 groups of soccer cards and 11 groups of baseball cards....

Step-by-step explanation:

First we have been asked that there are 16 soccer cards and 22 baseball cards into group. What is the greatest number of cards she can put in each group.

We have to find the GCF of 16 and 22

16 = 2*2*2*2

22= 2*11

Thus the GCF of 16 and 22 is 2. It means the greatest number of cards she can put in each group is 2.

How many groups of each type will there be?

16:22

Divide both the values by 2

8:11

Thus there will be 8 groups of soccer cards and 11 groups of baseball cards....

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<h3>Total snow fall for three days is 8.75 inches</h3>

<em><u>Solution:</u></em>

Given that,

Snow fell over the past three days

First\ day = 3\frac{2}{4}\ inches = \frac{14}{4}\ inches\\\\Second\ day = 3\frac{2}{4}\ inches = \frac{14}{4}\ inches\\\\Third\ day = 1\frac{3}{4}\ inches = \frac{7}{4}\ inches

<em><u>What was the total snowfall for the three days?</u></em>

Total snowfall = first day + second day + third day

Total\ snowfall = \frac{14}{4} + \frac{14}{4} + \frac{7}{4}\\\\Total\ snowfall = \frac{14 + 14 + 7}{4}\\\\Total\ snowfall = \frac{35}{4} \text{ or } 8.75\ inches

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3 years ago
If it takes 16 yards of material to make 5/2 costumes, how much material will be needed to make 19/2 costumes of that same size?
IRISSAK [1]

yards/costumes:16/(5/2) = X/(19/2)

Cross multiply.

(5/2)x = 152

Multiply both sides by 2/5.

x = 101 1/3 yards

7 0
3 years ago
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Below are two different functions, f(x) and g(x). What can be determined about their slopes?
worty [1.4K]
<h3>Answer: B) the function g(x) has a larger slope</h3>

===================================================

Explanation:

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The slope of g(x) is 5. Note how if we started at (0,-2) on the red line and moved up 5 and to the right 1, we arrive at (1,3) which is another point on the red line. You could use the slope formula

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Snezhnost [94]

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