US Department of Transportation As part of a study on transportation safety, the US Department of Transportation collected data
1 answer:
Answer:
- we can conclude that for every single unit of : x, y would be increased by 0.2871. and intersection of x and y will be through =1.5974
- it can be concluded that they are strongly positively correlated. There is strong and positive correlation between them. i.e the number of fatal accidents and the drivers under the age of 21
Step-by-step explanation:
WITH THE GIVEN DATA
A ) using regression to investigate the relationship between the number of fatal accidents and the percentage of drivers under the age pf 21
to fit into a regression line we must have ∝ and β
where β = = 0.2871
and ∝ = y - βx = - 1.5974
regression line = ∝ + β * x
insert values into regression line equation
regression line = -1.5974 + 0.2871 * x
we can conclude that for every single unit of : x, y would be increased by 0.2871. and intersection of x and y will be through =1.5974
B ) conclusion and recommendations can you derive from your analysis
it can be concluded that they are strongly positively correlated. There is strong and positive correlation between them. i.e the number of fatal accidents and the drivers under the age of 21
using the correlation coefficient ( r ) = = 0.8394
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Answer:
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Given:
Find:
Solution: In order to solve for n we need to add 8 to both sides which would cancel -8 on the right side and isolate n giving us the value of n.
<u>Add 8 to both sides</u>
Therefore, the final answer would be that n is equal to -11.
Answer:
<em>Felix earns total $594 per week.</em>
Step-by-step explanation:
Felix’s sales are $53000.
So, <u>the amount of sales over $4800 will be</u>:
Felix earns $450 per week and additional 3% of sales over $4800.
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Answer:
statistic value t= 5.43
p-value: < 0.00001.
Step-by-step explanation:
Hello!
To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.
The study variable is:
X: Max. penetration of a steel conduit.
The data of the sample
n= 45
sample mean X[bar]= 53.4
sample standard deviation S= 4.2
The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50
The hypothesis is:
H₀: μ ≤ 50
H₁: μ > 50
α: 0.05
To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.
Under the null hypothesis, the critical region and the p-value are one-tailed.
Critical value:
Rejection rule:
Reject the null hypothesis when t ≥ 1.68
t=
t= 5.43
The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.
p-value:
P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.
The p-value is less than α so the decision is to reject the null hypothesis.
Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.
I hope it helps!