Answer:
<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.
Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:
n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).
So, n can be written as 3 times another integer, thus n is divisible by 3.
<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.
Assume that n is divisible by 3. The above proof suggest that we write it as
n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).
As k, k+1, k+2 are three consecutive integers, we have completed our goal.
Step-by-step explanation:
Y = 3x - 1 ---- (1)
x - y = -9 ---- (2)
From Equation 2:
x - y = - 9
x + 9 = y
y = x + 9 --- (2a)
(1) - (2a):
0 = 3x - x - 1 - 9
0 = 2x - 10
2x - 10 = 0
2x = 10
x = 5 ---- sub into (1)
y = 3(5) - 1
y = 15 - 1
y = 14
The answer is -25
3-8=-5
-5*5=-25
Answer:
Top right square. It's mirroring the image on the other side of the y axis. So Quadrant 2
I believe The answer is -92
