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diamong [38]
3 years ago
14

For a charity race car event a sponsor committed to

Mathematics
1 answer:
lukranit [14]3 years ago
3 0
You need to put the numbers in y=mx+b format and you get y= 10x+100
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How many different 5​-letter radio station call letters can be made a. if the first letter must be Upper C comma Upper X comma U
Lady_Fox [76]

Answer:

a) 1,518,000

b) 2,284,880

c) 60,720

Step-by-step explanation:

a) a. if the first letter must be Upper C comma Upper X comma Upper T comma or Upper M and no letter may be​ repeated?

We draw 5 boxes, and based on that we will see the total possible cases. There are 26 alphabets

The first box should have C or X or T or M .No letter may be repeated.

Any                    Any             Any                 Any                    Any

5 alphabets    of the            of the              of the                 of the

C,X , T , M      remaining     remaining       remaining          remaining

                   25 alphabets   24 alphabets   23 alphabets   22 alphabets

Therefore; total possible call letters = 5 × 25 × 24 × 23 × 22 = 1,518,000

b)

The first box should have C or X or T or M Repeats as allowed

Any                    Any             Any                 Any                    Any

5 alphabets    of the            of the              of the                 of the

C,X , T , M      remaining     remaining       remaining          remaining

                   26 alphabets   26 alphabets   26 alphabets   26 alphabets

Therefore Total possible call letters = 5 × 26 × 26 × 26 × 26 = 2,284,880

c)   The first box should have   C,X , T , M  and end with S

So the last place if fixed, and we now have 25 alphabets. The first box can go in 5 ways. The next box then will have only 24 letters to choose from, as the first box has taken a letter and the last box already has S in it. Repetition not allowed

Any                    Any             Any                 Any                       S

5 alphabets    of the            of the              of the                  is fixed

C,X , T , M      remaining     remaining       remaining           here

                   24 alphabets   23 alphabets   22 alphabets  

Therefore Total possible call letters = 5 × 24 × 23 × 22  × 1 =  60,720

3 0
3 years ago
Give an example of a point that is the same distance from (3, 0) as it is from (7, 0). Find lots of examples. Describe the confi
Artist 52 [7]

Supposse that the distance from the point (x,y) to the point (3,0) is equal to the distance from  (x,y) to the point (7,0). Then, by the formula of the distnace we must have

\sqrt{(x-3)^2 + (y-0)^2}=\sqrt{(x-7)^2 + (y-0)^2}

cancel the square root and the (y-0)^2's, and then expand the parenthesis to obtain

x^2 - 6x + 9 = x^2 - 14x + 49

then, simplifying we obtain

8x = 40

therfore we must have

x=5

this means that the points satisfying the propertie must have first component equal to 5. So we can give a lot of examples of such points: (5,0), (5,7),(5,1/2), (5,-10),.... The set of this points give us a straight line and the points (3,0) and (7,0) are symmetric with respect to this line.

3 0
3 years ago
Which expression is equivalent to −3(−4m+9n)?
prohojiy [21]

Answer:

Yuhh the answers c dawhggg trus me i just did the same thing lawl!

Step-by-step explanation:

5 0
3 years ago
The measure of angle A in ABC is twice the measure of angle B and the measure of angle C is 20° less than the measure
diamong [38]

Answer:

m∡A = 100°

m∡B = 50°

m∡C = 30°

Step-by-step explanation:

let 'x' = m∡B;  50°

let '2x' = m∡A;   100°

let 'x-20' = m∡C;   30°

x + 2x + x - 20 = 180

4x - 20 = 180

4x = 200

x = 50

7 0
2 years ago
2. What inference can you make by comparing the measures<br> of variability?<br> I need the answer
d1i1m1o1n [39]

Answer:

16.02

Step-by-step explanation:

2. What inference can you make by comparing the measures

of variability?

I need the answer

16.02

7 0
2 years ago
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