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mina [271]
3 years ago
8

Which expression is equivalent

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
8 0

Hello from MrBillDoesMath!

Answer:

None of the provided answers is correct.

Discussion:

The correct answer is "none of the provided answers".  The last term in 9x^2 - 2y + 3x^2 - 3y^2   is

<h2>-3y^2</h2>

None of the answers provided have a y^2 term!  Check it out. Someone made a bo-bo and it wasn't MrBill!

Thank you,

MrB

almond37 [142]3 years ago
5 0

Answer:10 {x}^{2}  - 4y + 2 {x}^{2}  - y

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The vertical axis is called the y-axis. The point at which the two axes intersect is called the origin. The origin is at 0 on the x-axis and 0 on the y-axis.

Step-by-step explanation:

I believe this is correct, if not let me know and I will fix it. I'm sorry in advance if it is incorrect.

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2 (k + 2) = 8k - 5 - 3k
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256 equals j subtracted from 199
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-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
2 years ago
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