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umka21 [38]
3 years ago
14

Help me for number 7

Mathematics
2 answers:
KatRina [158]3 years ago
6 0

Answer:

17 dishes

Step-by-step explanation:

6+4+7 = 17

even though he broke two, he just has 15 intact dishes and 2 broken ones

tino4ka555 [31]3 years ago
5 0

Answer:

15 dishes left

Step-by-step explanation:

we are told Kurt had 6 green dishes, 4 red dishes, and 7 blue dishes. we are then asked how many dishes did he have <em>total</em> after breaking 2 dishes

the keyword here is total: we find the sum of the green, red, and blue dishes and subtract 2 which is the amount he broke

6 + 4 = 10

10+ 7 = 17

17 - 2 = 15

Kurt had 15 dishes left after he broke 2

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Function 1: y = 4x + 5
rosijanka [135]

Answer:

Option B is correct

Function 1, because the slope is 4 and the slope of function 2 is 2.

Step-by-step explanation:

Slope-intercept form:

The equation of line is given by:

y=mx+b

where, m is the slope and b is the y-intercept

As per the statement:

Function 1: y = 4x + 5

On comparing with [1] we have;

Slope of function 1  = 4

Function 2: The line passing through the points (1, 6) and (3, 10).

Using slope formula:

\text{Slope}= \frac{y_2-y_1}{x_2-x_1}

Substitute the given points we have;

\text{Slope}= \frac{10-6}{3-1}

⇒\text{Slope}= \frac{4}{2}

Simplify:

⇒\text{Slope}=2

⇒\text{Slope}= \frac{4}{2}

⇒ Slope of the function 2 is, 2

Since, function 1 is greater rate of change.( i.e 4 > 2)

Therefore,

Function 1  has the greater rate of change,  because the slope is 4 and the slope of function 2 is 2.

3 0
3 years ago
Read 2 more answers
Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph
Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

y=-\frac{7}{4}x+4

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

y_1=mx+b

And the second one, that is perpedicular to the one above:

y_2=nx+c

The slope of the second one is the negative inverse of the first one:

n=-\frac{1}{m}

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line:

y-y_1=m(x-x_1)

replace with the coordinates of the point and the slope and calculate:

\begin{gathered} y-(-7)=\frac{4}{7}(x-(-4)) \\ y+7=\frac{4}{7}(x+4) \\ y+7=\frac{4}{7}x+\frac{16}{7} \end{gathered}

Subtract 7 to both sides of the equation to write it in slope-intercept form:

\begin{gathered} y+7-7=\frac{4}{7}x+\frac{16}{7}-7 \\ y=\frac{4}{7}x-\frac{33}{7} \end{gathered}

Now you can graph both lines

8 0
1 year ago
Nzkmaldfoasdgfjsadof
lidiya [134]

Answer:

hiiiiiiiiiiiiiiiiiiiiiiii

Step-by-step explanation:

7 0
3 years ago
Can someone explain this to me please will give brainliest
KATRIN_1 [288]
The answer is A. for this, you have to set up a system of equations. the first one will be the area equation. since you know area=length x width, your equation will be LxW=50. the next equation is L=2W, since the length is two times the width. then, plug in 2W for the L in the other equation and you get 2W^2=50. divide by 2 and get W^2=25. square root both sides and you get W=5. plug back into the other equation to find L=10. Then, add the sides of the rectangle for the perimeter. 10+5+10+5=30.
3 0
3 years ago
Use what you know about the angle sum theorem for triangles and your algebra skills to solve for x and find the measure of all t
melomori [17]

Answer:

2x° = 45°, 3x° = 67.5°

Step-by-step explanation:

Sum of angles in a triangle = 180°

2x+3x+3x=180°

8x=180°

x=22.5°

2x=22.5°x2=45°

3x=22.5°x3=67.5°

8 0
3 years ago
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