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SIZIF [17.4K]
3 years ago
8

A rectangle has a height of a² + 3 and a width of a² + 2a + 5.

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

Area =  a^4+2a^3+8a^2+6a+15

Step-by-step explanation:

The area of a rectangle is given by:

Area = Height * Width

The expressions for height and width are given. We just need to multiply and add like terms (if applicable) to find the expression for the area of the rectangle.

Remember to use distributive property:

(a+b)(x+y) = ax + ay + bx + by

Thus, we have:

(a^2+3)(a^2+2a+5)\\=(a^2)(a^2)+(a^2)(2a)+(a^2)(5)+3a^2+6a+15\\=a^4+2a^3+5a^2+3a^2+6a+15\\=a^4+2a^3+8a^2+6a+15

THis is the expression for area.

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The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it
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Answer:

(a) 11.25 and 1.68  

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Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 15

             r = number of success

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                  which customer problems are resolved on the same day, i.e.;75%

So, here X ~ Binom(n=15,p=0.75)

(a) Expected number of problems to be resolved today = E(X)

            E(X) = \mu = n * p = 15 * 0.75 = 11.25

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(b) Probability that 10 of the problems can be resolved today = P(X = 10)

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(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

    = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}

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(d) Probability that more than 10 of the problems can be resolved today is

    given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)  

= \binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}

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