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Helga [31]
3 years ago
10

Divide for 2class .45÷6789

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0
<span>0.00006628369 is your answer for 0.45/6789</span>
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The difference between the prediction interval and the confidence interval is that A. the prediction interval is narrower than t
Kitty [74]

Answer:

<em>The prediction interval provides an interval estimation for a particular value of y while the confidence interval does it for the expected value of y. </em>

Step-by-step explanation:

<em>A</em><em>. the prediction interval is narrower than the confidence interval.</em>

the prediction interval is always wider than the confidence interval.

<em>B</em><em>. the prediction interval provides an interval estimation for the expected value of y while the confidence interval does it for a particular value of y.</em>

False

<em>C</em><em>. the prediction interval provides an interval estimation for a particular value of y while the confidence interval does it for the expected value of y. </em>

<em>True</em>

<em>D.</em><em> the confidence interval is wider than the prediction interval.</em>

the prediction interval is  wider

8 0
3 years ago
What are the equations for the asymptotes of this hyperbola
Fofino [41]

Answer:

its d

Step-by-step explanation:

5 0
4 years ago
Evaluate (z^2)^4/5z^5 when z=5 and simplify
wariber [46]
The answer to This question should be 25
4 0
3 years ago
Read 2 more answers
Jamila and Anica were rollerblading. They skated 14 miles in 12 hours if they skate at a contest rate how many miles did they sk
zloy xaker [14]

Answer:

1.1666 (The 6 is infinitive)

Step-by-step explanation:

14/12 (This gives you the average miles for one hour)

7 0
4 years ago
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days. a. Find the pro
MrMuchimi

Answer:

a. 0.313% (0.003134842261), b. 237.79 days (237.788095878)

Step-by-step explanation:

In this case, the length of pregnancies is a normally distributed variable, with a mean of 266 days, and a standard deviation of 15 days.  

A graph showing the distribution, with regions of interest for the answer, is presented below.

<h3>First Part: Find the probability of a pregnancy lasting 307 days or longer.</h3>

To answer the question regarding <em>the probability of a pregnancy lasting 307 days or longer</em>, it is necessary to calculate what the cumulative probability distribution value is at 307 days. By the way, according to the graph below, 307 days are quite far from the population mean (266 days).

Using the function <em>normaldist(266,15).cdf(307)</em>, from free Desmos software on Internet, we find that, at this length (307 days), the sum of all probabilities for all cases at this value is 99.69%  (0.996865157739).

Considering that the total area of the curve is 1, then <em>the probability of pregnancy lasting 307 days or longer</em> is 1 - 0.996865157739 or 0.003134842261 (or 0.00313), approximately 0.313%, a very low probabilty.

This probability is showed as the "light blue" region at the right extreme of the graph.

<h3>Second Part: Find the length that separates premature babies from those who are not premature.</h3>

To find the length that separates premature babies from those who are not premature, it is a question about <em>find the days related with the probability of 3% (or 0.03)</em> to find such premature babies. So, it is a question of finding a percentile (or 100-quantiles): given the cumulative normal distribution curve, what is the value (length of pregnancies) that represents this 3%.

Using the function <em>quantile(normaldist(266,15), 0.03)</em>, from free Desmos software on Internet, we obtained a value of 237.79 days (237.788095878) for the length of pregnacies of premature babies. In other words, those babies whose mothers have a length of pregnancy <em>lower</em> than 237.79 days are considered premature, or this is "the length that separates premature babies from those who are not premature".

The area below 237.79 days is the blue shaded region in the graph below, at the left extreme of it.

4 0
3 years ago
Read 2 more answers
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