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luda_lava [24]
3 years ago
11

1. A sphere is sliced so that the cross section does not intersect the center of the sphere.

Mathematics
2 answers:
stich3 [128]3 years ago
8 0
1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,

A = L*H = 12*6 = 72 cm^2

3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).

Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2

4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.

Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
vodomira [7]3 years ago
4 0
I just took the test its 33.3
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Show the work for 783 divided by 5
MissTica

Answer:

156.6 or 156 with a remainder of 3

Step-by-step explanation:

8 0
3 years ago
A regular hexagon inscribed in a circle is approximately 0.827 times the area of that same circle. What percentage of the circle
tatyana61 [14]

a. The percentage of the circle occupied by the hexagon is 82.7%

b. The percentage of the circle not occupied by the hexagon is 17.3%

Step-by-step explanation:

a regular hexagon inscribed in a circle is approximately 0.827 times the

area of that same circle

1. Assume that area the circle is x

2. Find the ratio of area hexagon to area circle

3. Change The ratio to percentage

4. Subtract area hexagon from area circle to find the area not occupied

    by the hexagon and do the same steps 2 and 3 with the area not

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∵ The regular hexagon inscribed in a circle

∴ Area the circle  > area of the hexagon

∵ Area the circle is x

∵ Area the hexagon is 0.827 times the area of the circle

∴ Area hexagon = 0.827(x)

∵ The ratio between area hexagon and area circle = \frac{0.827x}{x}

- Cancel x up with x down

∴ The ratio between area hexagon and area circle = 0.872

- Change the ratio to percentage by multiply it by 100%

∴ The percentage of area hexagon to area circle = 0.827 × 100%

∴ The percentage of area hexagon to area circle = 82.7%

a. The percentage of the circle occupied by the hexagon is 82.7%

∵ Area the circle is x

∵ Area the hexagon is 0.827 x

∴ The area not occupied by the hexagon = x - 0.827 x

∴ The area not occupied by the hexagon = 0.173 x

The ratio between area not occupied by the hexagon and area circle

= \frac{0.173x}{x}

- Cancel x up with x down

∴ The ratio between area not occupied by the hexagon and area

   circle = 0.173

- Change the ratio to percentage by multiply it by 100%

∴ The percentage of area not occupied by the hexagon to area

   circle = 0.173 × 100%

∴ The percentage of area not occupied by the hexagon to area

   circle = 17.3%

b. The percentage of the circle not occupied by the hexagon is 17.3%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

6 0
3 years ago
If m=5 and n = 2, find the value of 3mn
ki77a [65]

Answer:

30

Step-by-step explanation:

3mn=3x5x2=30

8 0
2 years ago
Please help me asap!
maxonik [38]

Answer:

\frac{7x + 7}{(x-3)(x+4)}

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Step-by-step explanation:

To simplify the expression multiply to create a common denominator.

Multiply the first fraction by (x-3) and the second fraction by (x+4).

\frac{3}{x+4} + \frac{4}{x-3}\\\\\frac{3(x-3)}{(x+4)(x-3)} + \frac{4(x+4)}{(x-3)(x+4)}

\frac{3(x-3)}{(x+4)(x-3)} + \frac{4(x+4)}{(x-3)(x+4)} \\\\\frac{3(x-3) + 4(x+4)}{(x-3)(x+4)}\\\\\frac{3x - 9 + 4x + 16}{(x-3)(x+4)}\\\\\frac{7x + 7}{(x-3)(x+4)}

Excluded values are values which make the denominator 0. This means (x-3)(x+4) cannot be 0. This means x cannot be 3 or -4. These are excluded values.

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3 years ago
For two consecutive spins, what is the theoretical probability of spinning a red first AND a blue second?
Sergio [31]
1/8 or 0.125 . . . .
5 0
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