Question

The rate (gallons per day) at which a pond loses water due to evaporation from one day after observation has started is give by w(t)=1/T2 (squared).
where t is the number of days after the first day. suppose we want to find out what the trend is for the total change in gallons in the pond. (Fill in the following table)
t is the number of days after the first day, and w is the number of gallons.

T: 1 2 10 50 100 200 500 1000
w(t): ? ? ? ? ? ? ? ?

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Answer 1

Answer:  see table below

Step-by-step explanation:

$\left\begin{array}{c|l}T&\qquad w(t)\\1&\dfrac{1}{1^2}=1\implies 1.00\\\\2&\dfrac{1}{2^2}=\dfrac{1}{4}\implies 0.25\\\\10&\dfrac{1}{10^2}=\dfrac{1}{100}\implies 0.01\\\\50&\dfrac{1}{50^2}=\dfrac{1}{2500}\implies 0.0004\\\\100&\dfrac{1}{100^2}=\dfrac{1}{10000}\implies 0.0001\\\\200&\dfrac{1}{200^2}=\dfrac{1}{40000}\implies 0.000025\\\\500&\dfrac{1}{500^2}=\dfrac{1}{250000}\implies 0.000004\\\\1000&\dfrac{1}{1000^2}=\dfrac{1}{100000}\implies 0.000001\\\end{array}\right$