Let 
be the set of all students in the <u>c</u>lassroom.
Let 
and 
be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.
We're given
i. We can split up into subsets of students that pass both physics and math 
and those that pass only physics 
. These sets are disjoint, so
ii. 9 students fails both subjects, so we find
By the inclusion/exclusion principle,
Using the result from part (i), we have
and so the probability of selecting a student from this set is
The first on is 5 added to q
Hi,
Let's simplify this equation step-by-step.
7−2(5−2x)−10x+25−4x−3
Distribute:
=7+(−2)(5)+(−2)(−2x)+−10x+25+−4x+−3
=7+−10+4x+−10x+25+−4x+−3
Combine Like Terms:
=7+−10+4x+−10x+25+−4x+−3
=(4x+−10x+−4x)+(7+−10+25+−3)
=−10x+19
Answer:
=−10x+19
Have a great day!
145%
200/200: 100%
90/200= 45%
