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stellarik [79]
3 years ago
10

Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6

inches, and Frame B has a length of 7 inches. 1. Without calculating, predict which frame has the shorter width. Explain your reasoning. 2. Find the width that you predicted to be shorter. Show your reasoning.​
Mathematics
1 answer:
Vilka [71]3 years ago
5 0

9514 1404 393

Answer:

  1. the longer frame (B) has the shorter width

  2. the shorter width is 6 3/7 inches, area divided by length

Step-by-step explanation:

The relation between area, length, and width is ...

  A = LW

Then the width is ...

  W = A/L . . . . .  inversely proportional to length

__

1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.

__

2. The width of frame B is ...

  W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in

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Step-by-step explanation:

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We can move the constant outside:

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Now, we will utilize the product rule. The product rule is:

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\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}

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