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stellarik [79]
3 years ago
10

Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6

inches, and Frame B has a length of 7 inches. 1. Without calculating, predict which frame has the shorter width. Explain your reasoning. 2. Find the width that you predicted to be shorter. Show your reasoning.​
Mathematics
1 answer:
Vilka [71]3 years ago
5 0

9514 1404 393

Answer:

  1. the longer frame (B) has the shorter width

  2. the shorter width is 6 3/7 inches, area divided by length

Step-by-step explanation:

The relation between area, length, and width is ...

  A = LW

Then the width is ...

  W = A/L . . . . .  inversely proportional to length

__

1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.

__

2. The width of frame B is ...

  W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in

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Answer:

404.98 m

Step-by-step explanation:

The angle of depression is 5°

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We need to find the height of the plane.

If we consider a triangle. 4629 meters will be the base and angle is 5°. Let h is the height of the plane. Using trigonometry to find it :

\tan\theta=\dfrac{x}{4629 }\\\\\tan(5)=\dfrac{x}{4629 }\\\\x=\tan(5)\times 4629 \\\\x=404.98\ m

So, the height of the plane is 404.98 m.

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Jobisdone [24]
The maximum profit is the y-coordinate of the vertex of the parabola represented by the equation.

P(c)=-20c^2+320c+5120 \\ \\
a=-20 \\
b=320 \\ \\
\hbox{the vertex } (h,k): \\
h=\frac{-b}{2a}=\frac{-320}{2 \times (-20)}=\frac{-320}{-40}=8 \\
k=f(h)=f(8)=-20 \times 8^2+320 \times 8+5120= \\
=-1280+2560+5120=6400

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Answer:

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Step-by-step explanation:

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Next, factor out i (i = √-1):

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Answer:

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