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Mathematics

2 answers:

gogolik [260]3 years ago

7 0

Y=2x I hope this helps u

zlopas [31]3 years ago

6 0

Answer:

y = 2x

Step-by-step explanation:

if 13 inches of snow has fallen over 6.5 hours, you just divide 13 by 6.5 to get the amount that has fallen each hour (2 inches)

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A quadrilateral with only one pair of parallel sides is called a

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Its called a Rhombus

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3 years ago

27÷624 as partial quotient

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3 years ago

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As a rule of thumb, the sampling distribution of the sample proportion can be approximated by a normal probability distribution

Gennadij [26K]

As a rule of thumb, the sampling distribution of the sample proportion can be approximated by a normal probability distribution whenever the sample size is large.

<h3>What is the Central limit theorem?</h3>

The Central limit theorem says that the normal probability distribution is used to approximate the sampling distribution of the sample proportions and sample means whenever the sample size is large.
Approximation of the distribution occurs when the sample size is greater than or equal to 30 and n(1 - p) ≥ 5.

Thus, as a rule of thumb, the sampling distribution of the sample proportions can be approximated by a normal probability distribution when the sample size is large and each element is selected independently from the same population.

Learn more about the central limit theorem here:

brainly.com/question/13652429

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2 years ago

Wind farm configuration is a significant issue as the upwind turbines generate maximal energy while creating wakes for downwind

lord [1]

Answer:

a) [24.114,29.2858]

b) Since 30 is not in the 95% confidence interval, there is a 95% probability that 30 is not the true mean WEP

Step-by-step explanation:

The 95% confidence interval is given by the interval

$\bf [ \bar x-z^*\frac{s}{\sqrt n}, \bar x+t^*\frac{s}{\sqrt n}]$

where

$\bf \bar x$ = 26.7 is the sample mean

s = 17.7 is the sample standard deviation

n = 180 is the sample size

Since the sample size is big enough, we can use the Normal N(0,1) to compute $\bf z^*$ and it would be 1.96(*) (a value such that the area under the Normal curve outside the interval [-z, z] is 5% (0.05))