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2 years ago

Find the product ( 1 1+1 ) ( 2 2+1 ) ( 3 3+1 )….. ( +1 ) for k=6

Mathematics

1 answer:

Sedaia [141]2 years ago

6 0

34=97+29=195 and this is your answer

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Rewrite without absolute value for the given conditions:

svlad2 [7]

Answer:

-2

Step-by-step explanation:

7 0

2 years ago

For questions 1 – 6, find the area of the circle to the nearest hundredth.<br> Any help appriciated!

Ganezh [65]

Step-by-step explanation:

The area of a circle is given by :

A = πr²

r is the radius of the circle

(4) Diameter = 22 cm

Since, radius = diameter/2

r = 11 cm

Now, area of the circle,

$A=\pi \times (11)^2\\\\A=380.13\ cm^2$

(5) Diameter = 30 cm

Since, radius = diameter/2

r = 15 cm

Now, area of the circle,

$A=\pi \times (15)^2\\\\A=706.85\ cm^2$

(6) Diameter = 4cm

Since, radius = diameter/2

r = 2 cm

Now, area of the circle,

$A=\pi \times (2)^2\\\\A=12.56\ cm^2$

So, the area of circles 4,5 and 6 are 380.13², 706.85² and 12.56² respectively.

4 0

2 years ago

HELP ASAP<br> 6+ x - y + 10=

Katena32 [7]

Answer:

x-y+16

Step-by-step explanation:

add the like terms, 6 and 10 which is 16. since the variables are not like terms, thats your final answer. hope it helped :)

7 0

2 years ago

3 Ximena draws an X shape in the coordinate plane as shown. Draw the images of

VARVARA [1.3K]

When a shape is rotated, it must be rotated around a point.

<em>See attachment for the image of each rotation.</em>

To do this, the top coordinates of the X shape will be transformed using the appropriate rotation rule; the same rule will then be applied to the other parts of the X shape.

The top coordinates of the X shape are:

$A = (0,0)$

$B = (1,0)$

$C = (3,0)$

$D =(4,0)$

For 90 degrees counterclockwise rotation, the rule is:

$(x,y) \to (-y,x)$

So, we have:

$A' = (0,0)$

$B' = (0,1)$

$C' = (0,3)$

$D' = (0,4)$

For 180 degrees rotation, the rule is:

$(x,y) \to (-x,-y)$

So, we have:

$A' = (0,0)$

$B' = (-1,0)$

$C' = (-3,0)$

$D' = (-4,0)$

For 270 degrees counter rotation, the rule is:

$(x,y) \to (y,-x)$

So, we have:

$A' = (0,0)$

$B' = (0,-1)$

$C' = (0,-3)$

$D' = (0,-4)$

See attachment for the image of each rotation