Find the product ( 1 1+1 ) ( 2 2+1 ) ( 3 3+1 )….. ( +1 ) for k=6
1 answer:
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Answer:
J(2, 5 )
Step-by-step explanation:
Using the section formula
=
=
=
= 2
=
=
=
= 5
Thus J = (2, 5 )