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netineya [11]
2 years ago
9

How to bring the polynomial to the standard form p(x) x^2-2x+4) (x^2+2x+4) ​

Mathematics
1 answer:
saveliy_v [14]2 years ago
5 0
<h3>Solution:</h3>

\rightarrow\sf((p(x) {x}^{2}  + 2x + 4)( {x}^{2}  + 2x + 4)) \\  = \sf  {ax}^{2}  + bx + c \\  = \sf(p(x) {x}^{2}  {x}^{2}  + p(x) {x}^{2} (2x) + p(x) {x}^{2}  \times 4 + 2x \times  {x}^{2}  + 2x(2x) + 2x \times 4 +  {4x}^{2}  + 4(2x) + 4 \times 4) \\  = \sf( {x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16) \\   \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16}}}

<h3>Answer:</h3>

\large\boxed{\sf{\red{{x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16}}}

\color{red}{==========================}

✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ

✍︎ꕥᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢꕥ

✍︎ꕥᴋɪᴍ ᴀʀᴀꕥ

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\boxed{\pink{\tt \leadsto Sum \ of \ first \ five \ terms \ is \ 50 . }}

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\boxed{\red{\bf \bigg\lgroup For \ answer \ refer \ to \ attachment \bigg\rgroup  }}

<h3><u>Related</u><u> </u><u>Infor</u><u>mation</u><u> </u><u>:</u><u>-</u><u> </u></h3>

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