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exis [7]
4 years ago
6

Use the chart to multiply the binomial by the trinomial.

Mathematics
2 answers:
gregori [183]4 years ago
7 0

Answer:

The product of (y+3)(y^{2}-3y+9) is y^{3}+27

Step-by-step explanation:

we need to find the product of binomial by the trinomial of the expression:

(y+3)(y^{2}-3y+9)

Multiply term wise,

⇒y\times y^{2}-y\times 3y+y\times 9+ 3\times y^{2} -3\times 3y +3\times 9

⇒y^{3}- 3y^{2}+9y+ 3y^{2} -9y +27

combine the line terms together,

⇒y^{3}- 3y^{2}+ 3y^{2} +9y-9y +27

⇒y^{3}+27

Hence, the product of (y+3)(y^{2}-3y+9) is y^{3}+27

Sauron [17]4 years ago
3 0
Y^3+27 is the answer

hope that helps!

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More info: Capillaries

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What is the missing term in the factorization?
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Un apostador pierde en su primer juego el 30% de su dinero, en el segundo juego pierde el 50% de lo que perdió; finalmente en el
sergiy2304 [10]

Responder:

26,62

Explicación paso a paso:

Sea x el dinero original que tenía el jugador:

si un jugador pierde en su primer juego el 30% de su dinero, la cantidad perdida será;

= 30/100 \ of \ x\\= 0.3x

Si en el segundo juego pierde el 50% de lo que perdió, entonces la cantidad perdida en el segundo juego será:

= 50/100 \ of \ 0.3x\\= 0.5 \times 0.3x\\= 0.15x

Si en el tercer juego pierde el 40% de todo lo que ha perdido, la cantidad perdida en el tercer juego será:

=\frac{40}{100} \ of \ (0.3x+0.15x) \\= 0.4(0.45x)\\= 0.2025x

Si la cantidad que le queda para seguir apostando es de 37 soles, entonces para calcular la cantidad original que tiene, sumaremos toda la cantidad perdida y la cantidad restante y equipararemos la cantidad original x como se muestra:

0,3x + 0,15x + 0,2025x + 37 = x

0,6525x + 37 = x

x-0,6525x = 37

0,3475x = 37

x = 37 / 0,3475

x = 106,48

La cantidad que tenía originalmente era de 106,48

75% de 106,48

= 75/100 * 106,48

= 0,75 * 106,48

= 79,86

Tomando la diferencia entre su monto original y su 75% será:

= 106.48-79.86\\= 26.62

3 0
3 years ago
Is x-y=1 a direct variation
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Answer:

Xy=1/5......

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