Answer:
27) Double replacement
28) 2NaOH + H2SO4 --> Na2SO4 + 2H2O
Answer:
The concentration of the NaOH solution CB = 0.251 M
Explanation:
The balanced equation of reaction is:
H2SO4 + 2NaOH ===> Na2SO4 + 2H2O
Using titration equation of formula
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)
NB is the number of mole of base = 2 (from the balanced equation of reaction)
CA is the concentration of acid = 0.1053 M
CB is the concentration of base = to be calculated
VA is the volume of acid = 17.88 mL
VB is the volume of base = 15.00mL
Substituting
0.1053×17.88/CB×15 = 1/2
Therefore CB =0.1053×17.88×2/15×1
CB= 0.251 M
A. As temperature increases, the molecules and atoms move faster. As temperature
Answer:
2.15 mg of uranium-238 decays
Explanation:
For decay of radioactive nuclide-

where N is amount of radioactive nuclide after t time,
is initial amount of radioactive nuclide and
is half life of radioactive nuclide
Here
,
and 
So,
so, N = 2.446 mg
mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg