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4 years ago

Which statement is part of kinetic molecular theory

Chemistry

1 answer:

VashaNatasha [74]4 years ago

3 0

Answer:

A. Gas particles are in constant motion.

Step-by-step explanation:

The first postulate of Kinetic Molecular Theory is that gas particles are in constant motion.

B is wrong. Kinetic Molecular Theory assumes that there are no attractive forces between the molecules.

C is wrong. Kinetic Molecular Theory assumes that collisions between molecules are elastic.

D is wrong. Kinetic Molecular Theory assumes that there are no attractive forces between the molecules of the gas and those of its container.

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Sodium hydroxide reacts with sulfuric acid according to the equation:

Lelechka [254]

Answer:

27) Double replacement

28) 2NaOH + H2SO4 --> Na2SO4 + 2H2O

6 0

3 years ago

A 15.00-mL sample of an NaOH solution of unknown concentration requires 17.88 mL of a 0.1053 M H2SO4 M solution to reach the equ

Anastasy [175]

Answer:

The concentration of the NaOH solution CB = 0.251 M

Explanation:

The balanced equation of reaction is:

H2SO4 + 2NaOH ===> Na2SO4 + 2H2O

Using titration equation of formula

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)

NB is the number of mole of base = 2 (from the balanced equation of reaction)

CA is the concentration of acid = 0.1053 M

CB is the concentration of base = to be calculated

VA is the volume of acid = 17.88 mL

VB is the volume of base = 15.00mL

Substituting

0.1053×17.88/CB×15 = 1/2

Therefore CB =0.1053×17.88×2/15×1

CB= 0.251 M

6 0

4 years ago

The atoms and molecules in a gas are in constant motion. Temperature is a measure of this motion. How are these related?

Ksivusya [100]

A. As temperature increases, the molecules and atoms move faster. As temperature

7 0

4 years ago

Read 2 more answers

Which the following atoms will not react with water? a. K b. Li c. Pb d. Na

Veseljchak [2.6K]

B. Li thats the anwser

8 0

3 years ago

Read 2 more answers

Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s

Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

$N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}$

where N is amount of radioactive nuclide after t time, $N_{0}$ is initial amount of radioactive nuclide and $t_{\frac{1}{2}}$ is half life of radioactive nuclide

Here $N_{0}=4.60 mg$ , $t=4.1\times 10^{9}yr$ and $t_{\frac{1}{2}}=4.5\times 10^{9}yr$

So, $N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}$

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0

3 years ago