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Katen [24]
3 years ago
5

A teacher tells the student to dlaw the same wave with double the frequency, while keeping the amplitude the same. How would the

student draw the new wave?

Chemistry
1 answer:
Mandarinka [93]3 years ago
8 0

Answer:

A.

Explanation:

Frequency is how often one complete cycle or wave takes place. Amplitude is the height of the wave from the midpoint to the crest.

The new drawing should have twice as many waves in the same period of time, with the same height wave.

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What is the chemical composition of the mobile phase in this experiment?
Alecsey [184]
H2SO.Mgslfurmobile phase in this experiment
6 0
3 years ago
If 14 moles of oxygen react with 14 moles of hydrogen to produce water, what is the
Leokris [45]
Hydrogen is the limiting reactant because when doing a stoichiometry equation for the reactants, hydrogen will be used completely by having a smaller yield and oxygen will be excess (7 moles to be exact)

7 0
3 years ago
With the Haber process, how many grams of hydrogen will be needed to make 0.3820 pounds of ammonia? Needed to 3 decimal places f
masya89 [10]

30.576 g of hydrogen

Explanation:

First we need to covert the pound in grams.

if        1 pound is equal to 453.592 grams

then  0.3820 pounds is equal to X grams

X = (0.3820 ×  453.592) / 1 = 173.272 grams

So we have 173.272 grams of ammonia.

Now we look at the chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):

3 H₂ + N₂ → 2 NH₃

number of moles = mass / molar weight

number of moles of ammonia = 173.272 / 17 = 10.192 moles

Now taking in account the chemical reaction, we formulate the following reasoning:

if         3 moles of hydrogen produce 2 moles of ammonia

then    Y moles of hydrogen produce 10.192 moles of ammonia

Y = (3 × 10.192) / 2 = 15.288 moles of hydrogen

mass = number of moles × molar weight

mass of hydrogen = 15.288 × 2 = 30.576 g

Learn more about:

problems with number of moles

brainly.com/question/13950919

brainly.com/question/13947602

#learnwithBrainly

4 0
4 years ago
A student is trying to identify a clear liquid that he finds in a beaker in the classroom. He thinks the liquid might be either
kumpel [21]

Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.

Explanation:

density

ρ

=

Mass

Volume

, and thus units of

g

⋅

m

L

−

1

are reasonable.

For this problem:

17.4

⋅

m

L

×

0.798

⋅

g

⋅

m

L

−

1

≅

14

⋅

g

but A i supposed?

3 0
3 years ago
Calculate the hydronium ion concentration in an aqueous solution with a poh of 4.33 at 25°c.
Jlenok [28]

Taking into account the definition of pH and pOH, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or  hydronium ion H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Definition of pOH</h3>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

<h3>Relationship between pH and pOH</h3>

The following relationship can be established between pH and pOH:

pOH + pH= 14

<h3>Concentration of hydronium ions</h3>

Being pOH= 4.33, pH is calculated as:

pH + 4.33= 14

pH= 14 - 4.33

<u><em>pH= 9.67</em></u>

Replacing in the definition of pH the concentration of hydronium ions is obtained:

- log [H₃O⁺]= 9.67

Solving:

[H₃O⁺]= 10⁻⁹ ⁶⁷

<u><em>[H₃O⁺]= 2.138×10⁻¹⁰ M</em></u>

Finally, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

Learn more about pH and pOH:

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#SPJ1

4 0
2 years ago
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