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3 years ago

How much volume would a 834.01g pile of sugar have given that it has a density of 1.59g/mL?

Chemistry

1 answer:

boyakko [2]3 years ago

7 0

Answer:

v = 534.5mL

m = 597.15g

Density = 9.23g/mL

Density = 9.125g/mL

Explanation:

Density = mass/ volume

For the first question

Density = 1.59g/mL

Mass = 834.01g

Volume = ?

Using the above formula we have 1.59 = 834.01/v

v = 834.01/1.59

v = 534.5mL

For the second question

Density =0.9167g/mL

Volume = 651.41mL

Mass =?

Using the above formula we have

0.9167 =m/651.41

Cross multiply

m = 0.9167 x 651.41

m = 597.15g

For the third question

Mass =803.44g

Volume=87.03mL

Density =?

Density = 803.44/87.03

= 9.23g/mL

For the fourth

Density = 56.85/6.23

= 9.125g/mL

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Answer:125.0964g

Explanation:

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Solid potassium chlorate (kclo3) decomposes into potassium chloride and oxygen gas when heated. how many moles of oxygen form wh

IrinaVladis [17]

Answer:

0.665 mol of O₂.

Explanation:

1. Molecular chemical equation:

2 KClO₃(s) → 2 KCl(s) + 3 O₂(g)

2. Mole ratios:

2 mol KClO₃ : 2 mol KCl : 3 mol O₂

3. Number of moles of KClO₃

Number of moles = mass in grams / molar mass

Molar mass of KClO₃ = 122.55 g/mol

Number of moles of KClO₃ = 54.3 g / 122.5 g/mol ≈ 0.44308 mol

3. Number of moles of O₂

As per the theoretical mole ratio 2 mol of KClO₃ produce 3 mol of O₂, then set up a proportion to determine how many moles of O₂ will be produced from 0.44038 mol of KClO₃.