Because there are several kind of cells in the blood, like red blood cell and white blood cell. They flow in the blood and will not precipitate, So it is called suspension.
Answer:
C. It does not participate in a decay series.
Explanation:
From this statement, we can deduce that a radioisotope that forms a stable isotope after it undergoes radioactive decay suggests that it does not participate in a decay series.
- It could have emitted any form of radioactive particles which can be alpha or beta.
- We do not know if it has a long or short half life because the value is not given.
- But since the radioactive decay in one step produces a stable isotope, we can conclude that it did not participate in a decay series.
- A decay series involves a radioactive decay in multiple steps.
The molar solubility of AgCl:
The molar solubility of AgCl in a 0.050 M NaCl solution is 8 x 
M 
What is solubility?
The solubility is the quantity of reagent required to saturate the solution or bring about the dissociation reaction's equilibrium.
Reaction:
The dissociation reaction of AgCl in water is:
⇄ 
Each mole of AgCl that dissolves in this reaction yields 1 mole of both and 
. The concentration of either the Ag or Cl ions would then be equal to the solubility.
Solubility= [] = []
Calculation:
in 0.050 M NaCl, the [] = 1 x 
ksp = [] x []
1.6 x 
= [
] x ( 5 x )
[] = 5 x 
x 1.6 x
[] = 5 x 1.6 x 
[] = 8 x M
Learn more about molar solubility here,
brainly.com/question/13202097
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Answer:
I don't know any except helium, sorry I couldn't do much.
The answer is <span>C.lithium (3), boron (5), and fluorine (9)</span>
