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lora16 [44]
3 years ago
11

Explain how you can use a quick picture to find 3× 2.7​

Mathematics
2 answers:
Mrac [35]3 years ago
7 0

Answer:

see the picture 8.1 is answer

pogonyaev3 years ago
6 0
Start by drawing 3 squares and using 2.7 as the perimeter.
You might be interested in
You are planning to put a new digital flat t.v on a wall that is 12ft long and 9ft high. the digital t.v has a diagonal of 72 in
Pie
Area of wall = 9 * 12 = 108 ft^2
Width of TV = x
Lenght = 2x
Diagonal of TV = 72 " = 6 ft


x^2+(2x)^2=6^2
x^2+4x^2=36
5x^2=35
x^2=36/5
x=sqrt(36/5)
Width = 2.68 ft.
Length = 2.68 * 5.36 = 14.36 ft^2
Area of wall - area of tv = 108 - 14.36 = 93.64 ft

7 0
3 years ago
How do you know when to use the Secant-Secant Product Theorem or the Secant-Tangent Product Theorem?
liq [111]
Asked and answered elsewhere.
brainly.com/question/9513977
6 0
3 years ago
How do I write an algebraic expression using words for a - b please respond urgently I need to this
elena-14-01-66 [18.8K]

Answer:

integer represented as a minus the integer represented as b

7 0
3 years ago
Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = pi over 2 ?
vladimir1956 [14]
tan(4x- \pi )= \frac{sin(4x- \pi )}{cos(4x- \pi )}

The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x)
It is where cos(4x-π) = 0

cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2

4x - π = π/2
4x = π/2 + π
4x = 3π/2
x = 3π/8

4x - π = 3π/2
4x = 3π/2 + π
4x = 5π/2
x = 5π/8
This ones outside the interval (5π/8 > π/2) , try -π/2

4x - π = -π/2
4x = -π/2 + π
4x = π/2
x = π/8

Asymptotes are π/8 and 3π/8




4 0
4 years ago
2. Use the following picture for this question:
Art [367]

Answer:

a.  24\sqrt{3}  and 41.6

b.  52.1

Step-by-step explanation:

a.

Considering the left side triangle the blue dotted side is the side "opposite" to the angle given and the side 24 is the side that is "adjacent" to the angle given. The trigonometric ratio tan relates opposite to adjacent. Also, let the blue dotted side be y.

<u>Note:</u> the exact value of tan 60 is \sqrt{3}

Thus, we can write Tan(60)=\frac{y}{24}\\y=24*Tan(60)\\y=24*\sqrt{3} \\y=24\sqrt{3}

Approximate value (rounded to nearest tenth):  24\sqrt{3} =41.6

b.

Considering the triangle to the right, the side "opposite" to the angle given (53 degrees) is 41.6 (just found in part (a)) and the side "hypotenuse" (side opposite to 90 degree angle) is x. The trigonometric ratio sine relates opposite and hypotenuse.

Thus we can write and solve:

Sin(53)=\frac{41.6}{x}\\x=\frac{41.6}{Sin(53)}=52.1

4 0
3 years ago
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