Question

What is the magnitude of the electric field produced by a charge of magnitude 5.00 μC at a distance of 2.00 m?

Answer 1

Answer:

See answer below

Explanation:

Hi there,

To find the magnitude of electric field from a single charge, the following formula is used:

$E=k \frac{q}{r^2}$  where q is the charge in Coulombs (C), and r is the distance from the center of the charge in metres (m). k is the constant:

$k= 8.99*10^{9}$  $N*m^2/C^2$

Put q in C: q=5.00*10^(-6)

Plug in values:

$E=(8.99*10^{9} )\frac{5.00*10^{-6} }{(2.00)^2} N/C$

$E = 1.124*10^{4} N/C$