False. The soul is comprised of jiva and atman. True. In Hindu households it is common for women to lead household worship.
Answer:
None
Explanation:
The desired homozygous dominant genotype is AABBCCDDEE. To have an offspring with genotype "AABBCCDDEE", at least one copy of the dominant alleles for the genetic loci should be present in either of the parent. However, both the parents are homozygous recessive for all the five mentioned genetic loci and therefore, cannot have a progeny with homozygous dominant genotype "AABBCCDDEE". All the progeny of a cross between the two parents each with genotype "aabbccddee" would have homozygous recessive for all the give loci.
aabbccddee x aabbccddee = All aabbccddee
They are usually held out for a period of FOUR TO SIX WEEKS after diagnosis. Splenomegaly is an infectious disease that corrupt the spleen and the enlarged spleen usually persist even after all the symptoms have disappeared. Because of this, athletes should not resume active exercise too soon. Generally, the shortest period after which it is okay to resume active exercise is four weeks after all the symptoms have gone.
Answer:
a zygote, which is created when a male and a female gametes join…
Explanation:
Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross
