Answer:
33%.
Explanation:
The 4% population is red-hair due to the recessive mutation in melanocortin 1 receptor (MC1R).
Since, the population is in Hardy-Weinberg equillibrium- laet the frequency of recessive allele with red - hair is 'q' and the frequency of dominant allele in the population is 'p'.
q=0.2
According to hardy-weinberg equillibrium
(p+q)=1
p=1-q
p=1-0.2
p=0.8.
The total population with non red hair is calculated by
=
= 0.64 + 0.32
= 0.96
The percentage of the population with non red headed carrier for MC1Rr is calculated by:
=0.32/0.96*100
=33%
Thus, the correct answer is (B).
Simply place a 2 above each ...... gene pair and a one above each .... gene pair. Then multiply the numbers together to obtain the total number of different possible gametes.
<u><em>This is a tip,hope it helps!</em></u>
Answer:
Aristotle
Explanation:
Aristotle created his own system for mapping the stars first, the others studied and discovered things in different subjects. :)
Answer:
Chromosomes
Explanation:
Chromosomes contains gentic information and is called DNA.
Answer:
63.55 amu
Explanation:
The average atomic mass of an element can be calculated by multiplying the decimal abundance of each isotope of that element by the relative atomic mass and summing them up. That is;
Average atomic mass = {atomic mass of isotope 1 × decimal abundance of Isotope 1} + {atomic mass of isotope 2 × decimal abundance of isotope 2}
According to this question, two most abundant isotopes of copper contain 34 and 36 neutrons. The atomic mass of each isotope can be found by adding the no. of neutrons to the atomic number/proton no., which is 29.
Atomic mass of Isotope 1= 34 + 29 = 63
Atomic mass of Isotope 2= 36 + 29 =65
Decimal abundance of each isotope = percentage abundance ÷ 100
Isotope 1 (with 34 neutrons) = 72.5% = 72.5/100 = 0.725
Isotope 2 (with 36 neutrons) = 100 - 72.5 = 27.5% = 27.5/100 = 0.275
Therefore, the average atomic mass
= {63 × 0.725} + {65 × 0.275}
= {45.675} + {17.875}
= 63.55
Hence, the average atomic mass of copper is 63.55 amu
