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3 years ago

What is 5(x+20) = 7x+30?

Mathematics

2 answers:

Maru [420]3 years ago

6 0

Answer:

$x=35$

Step-by-step explanation:

Step 1: Distribute

$5(x + 20) = 7x + 30$

$(5 * x) + (5 * 20) = 7x + 30$

$5x + 100 = 7x + 30$

Step 2: Subtract 5x from both sides

$5x + 100 - 5x = 7x + 30 - 5x$

$100 = 2x + 30$

Step 3: Subtract 30 from both sides

$100 - 30 = 2x + 30 - 30$

$70 = 2x$

Step 4: Divide both sides by 2

$70 / 2 = 2x / 2$

$35 = x$

Answer: $x = 35$

anastassius [24]3 years ago

3 0

Answer: 35

Step-by-step explanation:

Simplifying

5(x + 20) = 7x + 30

Reorder the terms:

5(20 + x) = 7x + 30

(20 * 5 + x * 5) = 7x + 30

(100 + 5x) = 7x + 30

Reorder the terms:

100 + 5x = 30 + 7x

Solving

100 + 5x = 30 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.

100 + 5x + -7x = 30 + 7x + -7x

Combine like terms: 5x + -7x = -2x

100 + -2x = 30 + 7x + -7x

Combine like terms: 7x + -7x = 0

100 + -2x = 30 + 0

100 + -2x = 30

Add '-100' to each side of the equation.

100 + -100 + -2x = 30 + -100

Combine like terms: 100 + -100 = 0

0 + -2x = 30 + -100

-2x = 30 + -100

Combine like terms: 30 + -100 = -70

-2x = -70

Divide each side by '-2'.

x = 35

Simplifying

x = 35

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step by step explanation:

In the question,

Since the triangle two sides of the traingle is equal, it is an isosceles triangle.

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3 years ago

Joseph flew home from vacation with a heavy bag. With the first airline he flew, Joseph had to pay $27 to check his bag, plus $2

liubo4ka [24]

Answer:

Step-by-step explanation:

Flight A :

Checked bag fee = $27

Additional fee per overweight limit = $24

Flight B:

Checked bag fee = $16

Additional fee per overweight limit = $25

Since, the total amount paid for the package on both flights are the same ;

Let x = mass of bag above the weight limit.

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3 years ago

If f(x)= x/2-2 and g(x)= 2x^2+x-3, find (f+g)(x).

adelina 88 [10]

Answer: B. $2x^2 + \frac{3x}{2} - 5$

Step-by-step explanation:

Here, the given functions are,

$f(x) = \frac{x}{2} - 2$

$g(x) = 2x^2 + x - 3$

$(f+g)x = f(x) + g(x)$

$(f+g)x=\frac{x}{2} - 2 + 2x^2 + x - 3$

$(f+g)x=\frac{3x}{2} - 5 + 2x^2$

$(f+g)x=2x^2 + \frac{3x}{2} - 5$

Option B is correct.

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3 years ago

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