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Readme [11.4K]
3 years ago
15

8 and 1 fifth + 3 and 8 fifteenths=

Mathematics
2 answers:
ale4655 [162]3 years ago
8 0
11 and 11/15 is the answer
viva [34]3 years ago
6 0
(8 + 5) + (3 + 120)
  \     /        \        /
  (13)   +    (123)

(8 + 5) + (3 + 120) =  256
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(82 POINTS AND BRAINLYEST)
algol13

Answer:

4 inches

Step-by-step explanation:

The equation for volume of a rectangular prism is V=lwh, where l=length, w=width, h=height.

We are given the volume, length, and width, so let's put those in and solve for the height.

V = lwh

660.24 = 13.1*12.6*h

660.24=165.06h

660.24/165.06 = h

4 = h

<u>The height is 4 inches.</u>

7 0
3 years ago
Read 2 more answers
The area of a rectangular field is 8811 m2. if the width of the field is 89m, what is the length?
xeze [42]
Length = 99 because...
since you multiply to get the area, in order to find the missing term of an area (in this case its length), you do the opposite of what you started with...so if you multiplied to get the area, you need to divide to get the missing side...
so 8811 divided by 89 = 99
99 x 89 = 8811
4 0
3 years ago
The difference of two perfect cubes is 386. If the cube root of the smaller of the two numbers is 7, then the cube root of the l
choli [55]

Answer:

9

Step-by-step explanation:

Let the two perfect cubes be x and y where x > y.

According to the given conditions:

{x}^{3}  -  {y}^{3}  = 386...(1) \\ y = 7...(2) \\ plug \: y = 7 \: in \: equation \: (1) \\  {x}^{3}  -  {7}^{3}  = 386 \\ {x}^{3}  -  343 = 386 \\ {x}^{3}     = 343  +  386 \\ {x}^{3}     = 343  +  386 \\ {x}^{3}   = 729 \\ x =  \sqrt[3]{729}  \\ x = 9

Thus the cube root of the larger number is 9.

8 0
3 years ago
Heather is trying to decide what classes to take next year. She must take one of each and can choose from 3 math classes, 2 scie
Lostsunrise [7]
I think the answer is 12 cause you have to add
4 0
3 years ago
Read 2 more answers
What are the possible values of x for the following functions? f(x)=2-x/x(x-1)
nevsk [136]

The possible values of x for the following functions are values on real number except 0 and 1

<h3>Domain of a function</h3>

The domain of a function are the values of the independent variable for which it exists.

Given the function below

f(x)=2-x/x(x-1)

The function does not exist at the. point where the denominator is zero. From the function given, the function does not exist when;

x(x -1) = 0

x = 0 and x = 1

Hence the possible values of x for the following functions are values on real number except 0 and 1

Learn more on domain of a function here; brainly.com/question/1770447

#SPJ1

5 0
1 year ago
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