Multiply the numerator and denominator by √2
10√2/2
Simplify
5√2
Answer:
(look at this equation) y=3x+2
Step-by-step explanation:
1. 2y-6x=4
2. Add -6x over to the other side
3. Subtract 2 from both sides
4. Look and see which points according to the equation that I answered for you.
A. 8.53 units is the length of the straight which is perpendicular to the straight line CD
Answer:
19.9 miles
Step-by-step explanation:
In this problem we have:
is the distance travelled during the 1st day
is the distance travelled during the 2nd day
is the distance travelled during the 3rd day
is the distance travelled during the 4th day
We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:
Which can be rewritten using the general formula:
This means that
By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:
So, the distance travelled on the 7th day is 19.9 miles.
Solve each of the equations independently, then determine if the are continuous or discontinuous.
15≥-3x [start here]
-5≤x [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!]
x≥-5 [just turned around for analysis]
Next equation:
2/3x≥-2 [start here]
x≥-2(3/2) [multiply both sides of the equation by the reciprocal, 3/2)
x≥-3
So, (according to the first equation) all values of x must be greater than, or equal to -5.
(According to the second equation) all values of x must be greater than, or equal to -3.
So, when graphed on a number line, both equations graph in the same direction, so they are continuous.
