(4,3) is a solution for y=3x-9 but not y=1/2+1.
The total number of tries = 10
The tries are { <span>110 111 100 000 101 111 100 000 011 010 }
</span><span />
Where: 0 representing heads and 1 representing tails
The tries which are heads came up more than once in 3 coin flips { 100 000 100 000 010 }
The number of the tries which are heads came up more than once in 3 coin flips = 5
∴ The probability of heads coming up more than once in 3 coin flips = 5/10 = 1/2
The sum is the gcf, if 60 plus 84 is 148 then wouldn't it be 148 that's what they all have in common, you can use a calculator to figure this out like say 148 times 2 equals 296, divide 296 by 60. Does it go in?
Answer:
Step-by-step explanation:
C)3:2:6
Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
