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xxMikexx [17]
3 years ago
7

The substance which is dissolved in a solution is called

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
8 0
The substance that dissolves in a solution is called a solute.

This is because a solution is made up of 2 parts, the solute, which dissolves to make the solution, and the solvent, which is the substance that dissolves the solute.

I hope this helps!!

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A graduated cylinder contains 100.0 mL of
Paul [167]

Answer:

3 g/mL

Explanation:

density is mass divided by volume

The mass of the object is 450g, and the volume is 150mL (the water level changes by 150mL).

450g/150mL = 3 g/mL

6 0
3 years ago
A compound containing only carbon, hydrogen, and oxygen is analyzed using combustion analysis. When 50.1 g of the compound is bu
juin [17]

Answer:

C_{3}H_4O_2

Explanation:

Hello,

In this case, since the carbon of the initial compound is present in the carbon dioxide product, we can compute the mass and moles of carbon in the compound:

n_C=91.8g CO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2} =2.09molC\\\\m_C=91.8g CO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2}*\frac{12gC}{1molC} =25.0gC

Next, the mass and moles of hydrogen in the compound, is contained in the yielded amount of water, thus, we compute the mass and moles of hydrogen in the compound:

n_H=25.1gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =2.79molH\\\\m_H=25.1gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} *\frac{1gH}{1molH} =2.79gH

In such a way, the mass of oxygen comes from the mass of the compound minus the mass of carbon and oxygen:

m_O=50.1g-25.0g-2.79g=22.31gO

And the moles:

n_O=22.31gO*\frac{1molO}{16gO}=1.39molO

Then, we compute the subscripts by diving the moles of C, H and O by the moles of oxygen as the smallest moles:

C:\frac{2.09}{1.39}=1.5 \\\\H:\frac{2.79}{1.39}=2\\ \\O:\frac{1.39}{1.39} =1

After that, we write:

C_{1.5}H_2O

Which must be shown in whole number only, thereby we multiply the subscripts by 2, so the empirical formula turns out:

C_{3}H_4O_2

Best regards.

5 0
3 years ago
What mass of methane (in g) must be burned in order to liberate 12567 kJ of heat?
Ierofanga [76]

Answer:

Mass of methane required in gram = 226.35 gram (Approx.)

Explanation:

Given:

Heat energy used = 12,567 kJ

Missing data;

Δcombustion = 891  kJ/mol

Find:

Mass of methane required in gram

Computation:

Number of mol methane burned = Heat energy used / Δcombustion

Number of mol methane burned = 12,571 / 891

Number of mol methane burned = 14.1088 mol

1 mol of methane in gram = 16.043 grams

So,

Mass of methane required in gram = Number of mol methane burned x 1 mol of methane in gram

Mass of methane required in gram = 14.1088 x 16.043

Mass of methane required in gram = 226.3474

Mass of methane required in gram = 226.35 gram (Approx.)

4 0
3 years ago
Label the molecular shape around each of the central atoms in the amino acid glycine. hint
svetlana [45]

The Structure of Glycine is attached below and each central atom is encircled with different colors.

Molecular Shape around Nitrogen Atom (Orange):

As shown, Nitrogen is making three single bonds with two hydrogen atoms and one carbon atom hence, it has three bonded pair electrons and a single lone pair of electron. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Trigonal Pyramidal.

Molecular Shape around Carbon Atom (Green):

As shown, Carbon is making four single bonds with two hydrogen atoms and one nitrogen atom one with carbon atom of carbonyl group hence, it has four bonded pair electrons. Therefore, according to VSEPR theory it has Tetrahedral geometry.

Molecular Shape around Carbon Atom (Blue):

As shown, Carbon is making two single bonds with oxygen and carbon atoms and a double bond with oxygen. Hence, it has a Trigonal Planar geometry.

Molecular Shape around Oxygen Atom (Red):

As shown, Oxygen is making two single bonds with one carbon atoms and one hydrogen atom hence, it has two bonded pair electrons and two lone pair of electrons. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Bent.


6 0
3 years ago
Read 2 more answers
The pressure the gas exert the walls of the container will decrease because the gas particles hit the wall of the container
ser-zykov [4K]
The statement is false. The pressure of a gas do not decrease as the gas molecules hit the walls of the container. According to the Kinetic Molecular Theory, collisions of the gas molecules or with the walls of the container are perfectly elastic. This means that energy is not lost as the molecules collide with each other or with the walls of the container.
5 0
4 years ago
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