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White raven [17]
3 years ago
12

A graduated cylinder contains 100.0 mL of

Chemistry
1 answer:
Paul [167]3 years ago
6 0

Answer:

3 g/mL

Explanation:

density is mass divided by volume

The mass of the object is 450g, and the volume is 150mL (the water level changes by 150mL).

450g/150mL = 3 g/mL

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Which fundamental mechanisms appear in the reaction between pyridinium chlorochromate and a secondary alcohol
oksano4ka [1.4K]

The idea is to foretell the formation of a carbonyl compound by the reaction between alcohol and too much pyridinium chlorochromate. An oxidizing agent called pyridinium chlorochromate converts the alcohol group into the 1carbonyl group.

The carbonyl molecule that results from the reaction will depend on the reactant's OH group. Pyridinium chlorochromate [PCC] converts primary OH to aldehydes, whereas it converts secondary OH to ketones, and oxidation of tertiary OH has little effect. Alcohols and pyridinium chlorochromate [PCC] react to create a carbonyl molecule.

From primary alcohols to aldehydes and from secondary alcohols to ketones, pyridinium chlorochromate oxidizes alcohols one step up the oxidation ladder. pyridinium chlorochromate will not oxidize aldehydes to carboxylic acids, in contrast to chromic acid. Comparable to Pyridine (the Collins reagent) and CrO3 will both oxidize primary alcohols to aldehydes. Here are two instances of pyridinium chlorochromate being used.

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6 0
2 years ago
This solid is ductile and conducts electricity
AVprozaik [17]
The answer would be a metal, most likely copper. hope this helped (:
8 0
4 years ago
Ozone, o3, is a product in automobile exhaust by the reaction represented by the equation no2(g) + o2(g) --> 3no(g) + o3(g).
svetoff [14.1K]

Answer: 2.1 g mass of ozone(O_{3}) is predicted to form from the reaction of 2.0 g NO_{2} in a car's exhaust and excess oxygen

Given information : Mass of NO_{2} = 2.0 g and O_{2} is in excess.

We need to calculate the mass of ozone (O_{3})

Mass of ozone(O_{3}) is calculated with the help of mass of NO_{2} using stoichiometry.

NO_{2} + O_{2}\rightarrow NO + O_{3}

Step 1 : Convert grams of NO_{2} to moles of NO_{2}.

Moles = \frac{Grams}{Molar mass}

Molar mass of NO_{2} = 46.0 g/mol

Moles = \frac{2.0g}{46.0\frac{g}{mol}}

Moles of NO_{2} = 0.043 mol

Step 2 : Find the moles of O_{3} using moles of NO_{2}.

Moles of O_{3} is calculated by using moles of NO_{2} with the help of mole ratio.

A mole ratio is ​the ratio between the amounts in moles of any two compounds involved in a chemical reaction. The mole ratio may be determined by examining the coefficients in front of formulas in a balanced chemical equation.

From the balanced chemical equation we can see that coefficient of NO_{2} is 1 and coefficient of O3 is 1 , so mole ratio of O_{3} to NO_{2} is 1:1

Moles of O_{3} = (0.043 mol NO_{2})\times \frac{(1 mol O_{3})}{(1 mol NO_{2})}

Moles of O_{3} = (0.043)\times \frac{(1 mol O_{3})}{(1)}

Moles of O_{3} = 0.043 mol

Step 3 : Convert moles of O_{3} to grams of O_{3}

Grams = Moles X Molar mass

Molar mass of O_{3} = 48.0 g/mol

Grams = (0.043 mol O_{3})\times (\frac{48 g O_{3}}{1 mol O_{3}})

Grams = (0.043)\times (\frac{48 g O_{3}}{1})

Grams = 2.1 g O_{3}

Note : The above three steps can also be done using a single step setup.

Grams of O_{3} = (2.0 gNO_{2})\times \frac{(1mol NO_{2})}{(46.0 g NO_{2})}\times \frac{(1 mol O_{3})}{(1 mol NO_{2})}\times \frac{(48.0 g O_{3})}{(1 mol O_{3})}

Grams of O_{3} = (2.0 )\times \frac{(1)}{(46.0 )}\times \frac{(1)}{(1)}\times \frac{(48.0 g O_{3})}{(1)}

Grams of O_{3} = 2.1 grams


4 0
3 years ago
Calculate the number of moles in 8.45 x 1023 C atoms
ankoles [38]

Answer:

1.40

Explanation:

8.45×10^{23} ×  \frac{1 mol}{6.022x10x^{23} } = 1.40318 ≈ 1.40 mol

3 0
2 years ago
Isotopes of an atom differ from the average atom by the number of __________.
adelina 88 [10]

Answer:

Neutrons

Explanation:

The number of neutrons varies from atom to atom, which results in isotopes. Isotopes are different forms of the same atom that vary by the number of neutrons they contain.

6 0
3 years ago
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