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noname [10]
3 years ago
12

A 200.0 ml quantity of 0.9 M HCl was titrated with an NaOH solution to reach the equivalence point. The goal was to determine th

e concentration of the NaOH solution. if 23.9 ml if the NaOH solution was required, what was the [NaOH]???
Chemistry
1 answer:
Anettt [7]3 years ago
6 0

Since the acid and base react in a one to one ratio, you can use the equation M1V1 = M2V2 to solve for M2, or the molarity of NaOH.

M1 = 0.9 M HCl

V1 = 200.0 mL HCl

M2 = ?

V2 = 23.9 mL NaOH

(0.9 M)(200.0 mL) = M2(23.9 mL) —> M2 = 7.53 M NaOH

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