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3 years ago

Identify the property: 3(9) + 3(7) = 3(9 + 7)

Mathematics

2 answers:

harina [27]3 years ago

6 0

Answer:

sorry mines wrong just took the test

Step-by-step explanation:

Aleks [24]3 years ago

4 0

3(9) = 27
3(7) = 21
3(9+7) = 48
27+21 = 48
48=48

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Serga [27]

Answer:

I think that the answer isssss B

5 0

2 years ago

Solve this equation <br> 6. 14=t -44

Marizza181 [45]

Are you solving for t?

5 0

3 years ago

Simplify ........ (256y²⁵⁶) ⅛<br>help asap!!!!!

AVprozaik [17]

Answer:

2y^32

Step-by-step explanation:

Since 2^8 = 256, the eighth root of 256 is 2.

Next, we find the power of y by multiplying 256 and 1/8: result is 32.

Complete answer: 2y^32

7 0

2 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

Determine whether 81a2 − 25z6 is a difference of two squares. If so, factor it. If not, explain why.

aev [14]

81 a² - 25 $z^{6}$ is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Step-by-step explanation:

The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs

a² - b² is a difference of two squares
a² - b² = (a + b)(a - b)

∵ The binomial is 81 a² - 25 $z^{6}$

∵ $\sqrt{81}$ = 9

∵ $\sqrt{a^{2} }$ = a

∴ $\sqrt{81a^{2}}=9a$

∵ $\sqrt{25}$ = 5

∵ $\sqrt{z^{6}}$ = z³

∴ $\sqrt{25z^{6}}=5z^{3}$

- The two terms have square root

∵ The sign between them is (-)

∴ 81 a² - 25 $z^{6}$ is a difference of two squares

∵ Its factorization is two identical brackets with different

middle signs

∵ 81 a² = 9a × 9a

∵ 25 $z^{6}$ = 5z³ × 5z³

- The terms of the two brackets are 9a and 5z³

∴ 81 a² - 25 $z^{6}$ = (9a + 5z³)(9a - 5z³)

81 a² - 25 $z^{6}$ is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Learn more:

You can learn more about the difference of two squares in brainly.com/question/1414397

#LearnwithBrainly

7 0

2 years ago